You flip a fair coin 7 times. What is the probability that the coin lands with the heads side up exactly 3 out of the 7 times?
1 answer:
Answer:
35/128 ≈ 0.2374
Step-by-step explanation:
The number of combinations of 7 things taken 3 at a time is ...
7·6·5/(3·2·1) = 7·5 = 35
The number of sequences in which the coins can land is 2^7 = 128.
Of those 128 sequences, 35 will have exactly 3 heads.
The probability is 35/128.
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1. 4/7 = 16/28
Check:
(4/7)(4/4) = 16/28 = 16/28
2. 40/15 = 8/3
Check:
(40/15)/(5/5) = 8/3
3. 15/6 = 5/2
Check:
(15/6)/(3/3) = 5/2
4. 8/11 = 56/77
Check:
(8/11)(7/7) = 56/77
5. 9/2 = 63/14
Check:
(9/2)(7/7) = 63/14
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Step-by-step explanation:
