Answer:
46 cm
Step-by-step explanation:
Let p represent the length in cm of 1 bap'ai; let k represent the length in cm of 1 bok'ai. Then we have ...
12p +2k = 100
10p +10k = 100
Subtracting the second equation from 5 times the first, we get ...
5(12p +2k) -(10p +10k) = 5(100) -(100)
50p = 400
p = 8 . . . . cm
Then the second equation tells us ...
10(8) +10k = 100
10k = 20
k = 2 . . . . cm
Then 5p+3k = 5(8) +3(2) = 46 cm.
The distance 5 bap'ai and 3 bok'ai is 46 cm.
Answer:
36
Step-by-step explanation:
permeter is solved by doing length+length+width+width so therefore you would do 13+13+5+5 which equals 36 as your answer
Answer:
a) 
b) 
c) 
d) 
Step-by-step explanation:
a) 
b) 
c) 
d) 
Answer:
Step-by-step explanation:
boat was at 43.2 m/s speed increase to 144 m/s
if the boat was moving 0 m/s and increased to 144 m/s - 43.2 m/s accelerating at 25.2 m/s², it would take the same amount of time
25.2 m/s² × x seconds = (144 - 43.2) m/s solve for x in seconds
x seconds = 100.8 m/s / 25.2 m/s²
x seconds = 4 (m/s /ms²) = 4 (m/s × s²/m) = 4 seconds the units match
x = 4 seconds
Answer: Well u would have to divide first and you would get 1 and what is left over would be the numerator which would be 6 and the denominator would stay the same.
Therefore saying that the answer will be 1 6/8
Step-by-step explanation:
