Basically just substitute
3(-2)-1-3(-2) = -6-1+6 = -1
The answer is -1.
Answer:
53,901
Step-by-step explanation:
Here is the complete question :
In which number does the digit 5 have a value that is ten times greater than the value of the digit 5 in the number 245,093?
43,567
45,248
53,901
562,011
In the number 245,093 :
3 = units
9 = tens
0 = hundred
5 = thousand
4 = ten thousand
2 = hundred thousand
the value of 5 in the number is 5000. the number that would have a value that it 10 times greater than 5 in 245,093 must occupy the value of ten thousand.
looking through the options, it is only in 53,901 that 5 occupies a value of ten thousand
I am looking on the answers, and there is only one case, when a or b or c or d pass: 3|x-3| + 2 = 14. So I assume, that before two is plus. Then:
3|x-3|+2=14 |minus 2
3|x-3|=12 |divide 3
|x-3|=4
From absolute value definition you've got two ways:
x-3=4 or x-3=-4
x=7 or x=-1
And answer d) passes
Answer:
The confidence limits for the proportion that plan to vote for the Democratic incumbent are 0.725 and 0.775.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
Of the 500 surveyed, 350 said they were going to vote for the Democratic incumbent.
This means that 
80% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The confidence limits for the proportion that plan to vote for the Democratic incumbent are 0.725 and 0.775.
Answer:
The answer is 6 1/5 feet in width.
Step-by-step explanation:
Since the formula for area is <em>wl</em> or <em>width </em>x <em>length</em>, we can utilize our reversive property to find our width by dividing the Area we are given by our length, giving us the missing width in return. Dividing 46.5 square feet by 7.5 feet gives us 6.2 feet, or 6 1/5 feet.
Hope this helps!
