3 years ago

What is the answerPlease help very urgent

Mathematics

1 answer:

Lorico [155]3 years ago

3 0

Answer:

Step-by-step explanation:

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What is 9x-7y=-7 in slope intercept form?

Novay_Z [31]

Slope intercept form is y = mx + b

So if you start with 9x - 7y = -7, the first thing you need to do is move the 9x to the other side of the equation by subtracting it from both sides.
9x - 7y = -7
-9x -9x

Now you have -7y = -9x -7

For the equation to be in slope intercept form now you should divide every term by the number in front of your y. In this case divide every term by -7
-7y = -9x -7
-7 -7 -7

That leaves you with: y = 9x/7 + 1

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3 years ago

For an angle 0 with the point (-20,-21) on its terminating side, what is the value of cosine ?

Karo-lina-s [1.5K]

check the picture below.

$\bf (\stackrel{a}{-20},\stackrel{b}{-21})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{-20}\\ b=\stackrel{opposite}{-21}\\ \end{cases} \\\\\\ c=\sqrt{(-20)^2+(-21)^2}\implies c=\sqrt{841}\implies c=29 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{-20}}{\stackrel{hypotenuse}{29}}~\hfill$