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2 years ago

What unique information is collected on preincident surveys for a multistory building?

Engineering

1 answer:

Anastasy [175]2 years ago

4 0

Interior command sites exists collected on preincident surveys for a multistory building

<h3>What is preincident surveys?</h3>

A quality pre-incident survey presents advanced knowledge of important issues such as building construction, building layout, dangerous materials storage, fire alarm or fire suppression system credentials, and special occupancy problems. Pre-incident planning surveys exist as one of the key ways to plan for an emergency in the fire service. Pre-incident planning surveys provide firefighters and other emergency responders with critical knowledge of structures. It exists agreed that the best time to retrieve critical information exists before an emergency appears.

Pre-incident planning permits emergency responders to anticipate the resources and procedures required to meet specific demands within their jurisdictions. The complexity of today's fire protection systems, combined with changing building construction processes, makes pre-incident planning imperative.

Hence, Interior command sites exists collected on preincident surveys for a multistory building.

To learn more about Interior command sites refer to:

brainly.com/question/28082998

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Masteriza [31]

Answer:

$P(37.5$

And we can find this probability with this difference:

$P(-2.5$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(-2.5$

So then the percentage usable are 94,6%

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the diameters of a population, and for this case we know the distribution for X is given by:

$X \sim N(37.8,0.12)$

Where $\mu=37.8$ and $\sigma=0.12$

We are interested on this probability

$P(37.5$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(37.5$

And we can find this probability with this difference:

$P(-2.5$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(-2.5$

So then the percentage usable are 94,6%

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Answer:

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Explanation:

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Answer:

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Explanation:

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Answer:

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Explanation:

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