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tamaranim1 [39]
1 year ago
5

A survey was carried out among 120 school children looked at which type of meat they preferred. 55%said they preferred lamb,20%

said they preferred chicken, 15% preferred duck and 10% turkey . calculate the number of children in each category
Mathematics
1 answer:
Readme [11.4K]1 year ago
4 0

No. of children in lamb, chicken, duck, and turkey category is 66, 24, 18 and 12 respectively.

<h3>What is percentage ?</h3>

Percentage is the value per hundredth.

According to the given question a survey was carried out among 120 school children looked at which type of meat they preferred. 55% said they preferred lamb,20% said they preferred chicken, 15% preferred duck and 10% turkey and we have to calculate no. of children in each category.

55% said they preferred lamb, So the no. of students i this category is

= (55/100)×120

= 66 children.

20% said they preferred chicken, So the no. of children in this category is

= (20/100)×120

= 24 children.

15% said they preferred duck, So the no. of children in this category is

= (15/100)×120

= 18 children.

10% said they preferred turkey, So the no. of children in this category is

= (10/100)×120

= 12 children.

learn more about percentage here :

brainly.com/question/19670755

#SPJ4

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Circumcenter- The point where the perpendicular bisectors of a triangle meets.

Orthocenter-The intersecting point for all the altitudes of the triangle.

To find out the circumcenter we have to solve any two bisector equations.

We solve for line AB and AC

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Slope of AB =\frac{-3-3}{-4-2}=1

Slope of the bisector is the negative reciprocal of the given slope.  

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Equation of AB with slope -1 and the coordinates (-1,0) is,  

(y – 0) = -1(x – (-1))  

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Mid point of AC = (\frac{2+2}{2},\frac{3-3}{2})=(2,0)

Slope of AC = \frac{-3-3}{2-2}=\frac{-6}{0}  

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of the perpendicular bisector = 0  

Equation of AC with slope 0 and the coordinates (2,0) is,  

(y – 0) = 0(x – 2)  

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By solving equation (1) and (2),  

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y+x=-1

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To find the orthocenter we solve the intersections of altitudes.

We solve for line AB and BC

So, mid point of AB =(\frac{2-4}{2},\frac{3-3}{2})=(-1,0)

Slope of AB =\frac{-3-3}{-4-2}=1

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of CF = -1  

Equation of AB with slope -1 and the coordinates (-1,0) gives equation CF  

(y – 0) = -1(x – (-1))  

y+x=-1………………(3)  

Similarly, mid point of BC =(\frac{-4+2}{2},\frac{-3-3}{2})=(-1,-3)

Slope of AB =\frac{-3+3}{-4-2}=0

Slope of the bisector is the negative reciprocal of the given slope.  

So, the slope of AD = 0

Equation of AB with slope 0 and the coordinates (-1,-3) gives equation AD

(y-(-3)) = 0(x – (-1))  

y+3=0

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Solve equation (3) and (4),

Put y=-3 in equation (3)

y+x=-1

-3+x=-1

x=2

Therefore, orthocenter(O)= (2,-3)


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