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Sophie [7]
3 years ago
14

I’ve done this before,I’m in 7th rn but I forgot how to do this

Mathematics
2 answers:
12345 [234]3 years ago
6 0

Answer:

the answer is 17/12 all u have to do is change it into a mix fraction

earnstyle [38]3 years ago
5 0

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{ \frac{17}{12}}}}}}

Step-by-step explanation:

\sf{ \frac{7}{12}  +  \frac{5}{6} }

Take the L.C.M of 12 and 6

To find L.C.M , first of all find the prime factors of each numbers.

12 = 2 × 2 × 3

6 = 2 × 3

Take out the common prime factors i.e 2 and 3

Also take out the other remaining prime factors : 2

Multiply those all prime factors and obtain L.C.M

L.C.M = Common factors × Remaining factors

= 2 × 3 × 2

= 12

\dashrightarrow{ \sf{ \frac{7 \times 1 + 5 \times 2}{12}}}

\dashrightarrow{ \sf{ \frac{7 + 10}{12}}}

\dashrightarrow{ \sf{ \frac{17}{12}}}

Hope I helped!

Best regards! :D

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The mean length of 6 childrens' big finger is 6.7cm.
yaroslaw [1]

Answer:

New mean length of these 17 people=11.62

Step-by-step explanation:

<em>Step 1: Determine the total length of children's fingers</em>

L=l×n

where;

L=total length (cm)

l=mean length (cm)

n=number of children

replacing;

L=6.7×6=40.2 cm

The total children's fingers length=40.2 cm

<em>Step 2: Determine the total length of adults fingers</em>

total length of adults fingers=mean length of adults fingers×number of adults

where;

mean length of adults=14.3

number of adults=11

replacing;

total length of adults fingers=(14.3×11)=157.3 cm

<em>Step 3: Determine the new mean length</em>

new mean length=total length of adults and children fingers/number of adults and children

where;

total length of adults and children fingers=157.3+40.2=197.5 cm

number of adults and children=11+6=17

replacing;

new mean length=197.5/17=11.62

7 0
3 years ago
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Answer:

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Step-by-step explanation:

Try using Symbolab, I use it all the time it gives the correct answer and it gives good explanations.

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Answer:

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Step-by-step explanation:

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What is d and how would I find its value
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