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2 years ago

The table shows the ages and weights of babies at a hospital.

Mathematics

2 answers:

zzz [600]2 years ago

8 0

I believe the answer is B) positive

2 years ago

Mr. Palmer does an experiment to investigate the effects of distractions on studying and learning.

Brums [2.3K]2 years ago

3 0

Answer:

Option (b) is correct.

The correlation between age and weight shown in the table is positive.

Step-by-step explanation:

Given: The table shows the ages and weights of babies at a hospital.

We have to determine the correlation between age and weight as shown in the table.

We first Plot these points to obtain the graph as show in attachment below.

Since, Using correlation calculator , we find the correlation as 0.83113

Which is positive

Thus, The correlation between age and weight shown in the table is positive.

As age increases the weight increase.Hence, positive.

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(-3.2) to the power of 0

stellarik [79]

Answer:

Step-by-step explanation:

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2 years ago

-4 + 6g, for g = 4 i need in a sentence

laiz [17]

Answer:

-4+6*4 = 20

Step-by-step explanation:

If g is equal to 4 the answer is 20

8 0

2 years ago

Avis purchased a Jeep for $12,480. Her down payment was $3,600. She paid the remainder in 48 monthly payments. Write a numerical

MrMuchimi

9514 1404 393

Answer:

(12480 -3600)/48

Step-by-step explanation:

Assuming a 0% interest rate, the monthly payment will be 1/48 of the amount remaining after the down payment:

(12480 -3600)/48

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2 years ago

The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.

VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

$\int\limits^2_{-1} {(f(x) - g(x))} \, dx$

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx$

We know that:

$\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}$

$\int\limits^{}_{} {1} \, dx = x$

$\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}$

Then our integral is:

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2} + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3} + (-1) - \frac{(-1)^2}{2} )$

The right side is equal to:

$(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6$

The bounded area is 5 + 5/6 square units.

3 0

2 years ago

Help please me please help me

Vinil7 [7]

Answer: (3, 18)

Step-by-step explanation: Where the lines corss the x does not go over 10 so the only other option is a 3. If you cut the box hori in half in you mind, the top half being 15-20 and the bottom half bring 10-14, then you can see the lines cross on the top half. Meaning it’s at 18 not 12.

3 0

2 years ago