Ally ran 5 miles in 36 minutes.
Ally's speed is (5 miles)/(36 minutes) = 0.13888 miles per minute.
At that speed, Ally would run 6 miles in (6 miles)/(0.13888 miles/min) = 43.2 minutes.
Ally runs faster than Sami, so Sami must take longer to run 6 miles than Ally.
The only time that is longer than 43.2 minutes is 48 minutes.
The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
Answer:
Arithmetic.
Common Difference: -24
Step-by-step explanation:
An arithmetic sequence is a sequence with the difference between two consecutive terms constant. The difference is called the common difference. A geometric sequence is a sequence with the ratio between two consecutive terms constant.
For arithmetic, to find the common difference we take any pair of successive numbers, and we subtract the first from the second.
For geometric, to find the common ratio can be found by dividing any term in the sequence by the previous term.
Answer:
D y-8 +2 ≤ -2+2
Step-by-step explanation:
y-8 ≤ -2
Add 2 to each side
y-8 +2 ≤ -2+2
