The area of each triangular face is
.. A = (1/2)*b*h
.. Aside = (1/2)*(6 cm)*(5 cm) = 15 cm^2
The area of the triangular base is
.. Abase = ((√3)/4)*s^2 = (√3)/4*(6 cm)^2 = 9√3 cm^2
The total surface area is the base area plus the area of the three sides.
.. Atotal = Abase + 3*Aside
.. = 9√3 cm^2 +3*15 cm^2
.. = (45 +9√3) cm^2
.. ≈ 60.6 cm^2
Actually, there's an error in the picture. The height of the side should be 4, and the length of the edge should be 5. Making that adjustment, the total area is 51.6 cm^2.
It is hard to tell what is intended. Not all answers are showing, so we can't "reverse-engineer" the problem from the answers.
MN = √2
it comes from √(1^2 + 1^2) = √2 (use phytagoras)
LK = 2 x MN = 2 √2
NK = √(2^2 + 1^2) = √5
ML = NK = √5
so the perimeter
√2 + 2 √2 + √5 + √5
3 √2 + 2 √5
Answer:
Answer is 80.36
Step-by-step explanation:
V=πr2h=π·2.12·5.8≈80.35566
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Answer: z < 4
z+4 > 2z
z+4-z > 2z-z ..... Subtract z from both sides
4 > z
z < 4
So the solution set for z is any number that is less than 4, which could be something like z = 2 or z = 3.
Answer:
89.804
Step-by-step explanation:
