The limit as a definite integral on the interval
on [2π , 4π] is
.
<h3>
What is meant by definite integral?</h3>
A definite integral uses infinitesimal slivers or stripes of the region to calculate the area beneath a function. Integrals can be used to represent a region's (signed) area, the cumulative value of a function changing over time, or the amount of a substance given its density.
Definite integral, a term used in mathematics. is the region in the xy plane defined by the graph of f, the x-axis, and the lines x = a and x = b, where the area above the x-axis adds to the total and the area below the x-axis subtracts from the total.
If an antiderivative F exists for the interval [a, b], the definite integral of the function is the difference of the values at points a and b. The definite integral of any function can also be expressed as the limit of a sum.
Let the equation be

substitute the values in the above equation, we get
=
on [2π, 4π],
simplifying the above equation

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Answer: 1296 cm³
Step-by-step explanation:
Since, the volume of a square pyramid is,

Where a = side of the square base,
h = height of the pyramid,
By the given diagram,
a = 18 cm,
h = 12 cm,
Hence, the volume of the given pyramid,



cube cm.
⇒ First option is correct.
9090 is 70% of 12,985.7143
The total length of the wire needed to make this shape is 162cm
<h3>Perimeter of a triangle</h3>
The perimeter of a triangle is the sum of the external side of the triangle.
Given the following parameters
Length of one side of the outside shape = 24cm
The side length of the smaller triangle = 24/4 = 6cm
The perimeter of the smallest triangle 3(6) = 18cm
The perimeter of the smaller triangle (at the middle) = 12(3) = 36cm
Total length of wire needed. = 3(24) + 3(18) + 36
Total length of wire needed = 72 + 54 + 36
Total length of wire needed = 162cm
Hence the total length of the wire needed to make this shape is 162cm
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