Answer:
C)
Step-by-step explanation:
Answer:
A. 7,348
Step-by-step explanation:
P = le^kt
intitial population = 500
time = 4 hrs
end population = 3,000
So we have all these variables and we need to solve for what the end population will be if we change the time to 6 hours. First, we need to find the rate of the growth(k) so we can plug it back in. The given formula shows a exponencial growth formula. (A = Pe^rt) A is end amount, P is start amount, e is a constant that you can probably find on your graphing calculator, r is the rate, and t is time.
A = Pe^rt
3,000 = 500e^r4
now we can solve for r
divide both sides by 500
6 = e^r4
now because the variable is in the exponent, we have to use a log

ln(6) = 4r
we can plug the log into a calculator to get
1.79 = 4r
divide both sides by 4
r = .448
now lets plug it back in
A = 500e^(.448)(6 hrs)
A = 7351.12
This is closest to answer A. 7,348
Convert all the improper fractions into mixed numbers, then simplify. Then, you do the operations.
Answer:
18
Step-by-step explanation:
xy + 4 = 40
xy = 40 - 4
xy = 36
What two numbers can b multiplied to give 36? Then add them.
9 + 4 = 13
18 + 2 = 20
6 + 6 = 12
12 + 3 = 15
The odd option is 18