Answer:
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Step-by-step explanation:
Solving for <em>Angles</em>
![\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Ba%5E2%20%2B%20b%5E2%20-%20c%5E2%7D%7B2ab%7D%20%3D%20cos%E2%88%A0C%20%5C%5C%20%5Cfrac%7Ba%5E2%20-%20b%5E2%20%2B%20c%5E2%7D%7B2ac%7D%20%3D%20cos%E2%88%A0B%20%5C%5C%20%5Cfrac%7B-a%5E2%20%2B%20b%5E2%20%2B%20c%5E2%7D%7B2bc%7D%20%3D%20cos%E2%88%A0A)
* Do not forget to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!
Solving for <em>Edges</em>
![\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20b%5E2%20%2B%20a%5E2%20-%202ba%5C%3Acos%E2%88%A0C%20%3D%20c%5E2%20%5C%5C%20c%5E2%20%2B%20a%5E2%20-%202ca%5C%3Acos%E2%88%A0B%20%3D%20b%5E2%20%5C%5C%20c%5E2%20%2B%20b%5E2%20-%202cb%5C%3Acos%E2%88%A0A%20%3D%20a%5E2)
You would use this law under <em>two</em> conditions:
- One angle and two edges defined, while trying to solve for the <em>third edge</em>
- ALL three edges defined
* Just make sure to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!
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Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:
- Two angles and one edge defined, while trying to solve for the <em>second edge</em>
- One angle and two edges defined, while trying to solve for the <em>second angle</em>
- ALL three angles defined [<em>of which does not occur very often, but it all refers back to the first bullet</em>]
* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.
I am delighted to assist you at any time.
The answers are:
A) V-Shaped (because absolute value graphs are v-shaped)
C) Opens up (because the leading coefficient is positive)
F) Symmetric with respect to the y-axis (if you look at the graph y= |x|, you see that the y-axis cuts through the middle of the "v-shape", and that it is symmetric)
You only need a common denominator for adding and subtracting! <span />
I am pretty sure it linear