The equation would be : 10y + 3x = 50
Hope this helps :)
Answer:
The surface area of the second cylinder is equal to ![9.33\ m^{2}](https://tex.z-dn.net/?f=9.33%5C%20m%5E%7B2%7D)
Step-by-step explanation:
we know that
If two figures are similar then
the ratio of their surfaces areas is equal to the scale factor squared
Let
z-------> the scale factor
x------> the surface area of the smaller cylinder (second cylinder)
y-------> the surface area of the original cylinder (first cylinder)
so
![z^{2}=\frac{x}{y}](https://tex.z-dn.net/?f=z%5E%7B2%7D%3D%5Cfrac%7Bx%7D%7By%7D)
Step 1
Find the scale factor
![z=\frac{2}{6}=\frac{1}{3}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B2%7D%7B6%7D%3D%5Cfrac%7B1%7D%7B3%7D)
Step 2
Find the surface area of the second cylinder
we have
![z=\frac{1}{3}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B1%7D%7B3%7D)
![y=84\ m^{2}](https://tex.z-dn.net/?f=y%3D84%5C%20m%5E%7B2%7D)
substitute and solve for x
![(\frac{1}{3})^{2}=\frac{x}{84}](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B3%7D%29%5E%7B2%7D%3D%5Cfrac%7Bx%7D%7B84%7D)
![x=\frac{1}{9}*84=9.33\ m^{2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B1%7D%7B9%7D%2A84%3D9.33%5C%20m%5E%7B2%7D)
Answer: its 37
Step-by-step explanation:
its 37