Answer:
The answer is B. 4,7.5,8
Step-by-step explanation:
Becouse A and C Both of them is Right-angled triangle and D is Obtuse triangle
Answer:
63 houses have been sold this year.
Step-by-step explanation:
There are 81 houses in the community. If 7/9 are sold this year, then all you have to do is multiplication.
In this case, you would multiply 81 by 7/9 to get your answer.
81/1 x 7/9:
Cancel out the 9 and the 81. Then the denominator will be 1 x 1 and the numerator would be 7 x 9. It would be 63 (7x9=63) over 1 (1x1=1) which is just 63. Make sure to include units.
Answer:
9:52
Step-by-step explanation:
First, let's rewrite "twenty-seven minutes past six", into a standard digital clock form. We could write 6:27. Now, it's easier to see that if we add 3 hours first, we would get to 9:27. And then if we add 25 minutes, we will get to 9:52.
We can see that, when the input is 5, the output is 24.
<h3>
How to evaluate an equation?</h3>
Here we have the equation:
Where y is the output and x is the input.
We want to evaluate it with the input as 5, so we need to replace the variable x by the number 5, we will get:
Then we can see that, when the input is 5, the output is 24.
If you want to learn more about evaluating functions:
brainly.com/question/1719822
#SPJ1
Answer:
- x = log(y/4)/log(1.0256)
- your answer for y=12 is correct
Step-by-step explanation:
The question is asking you to solve ...
y = f(x)
for x. (In other words, find the inverse function.)
You already did this using a constant for y. Do the same thing with y instead of the constant.
y = 4(1.0256^x)
y/4 = 1.0256^x . . . . . . . divide by 4
log(y/4) = x·log(1.0256) . . . . . take logs
log(y/4)/log(1.0256) = x . . . . . divide by the coefficient of x
Now, you have a model for x in terms of y, which is what the question is asking for.
x = log(y/4)/log(1.0256) . . . . . . . exact expression
When y=12, this is ...
x = log(12/4)/log(1.0256) ≈ 43.46 . . . . weeks
_____
This is a linear equation in log(y), so can be written as such:
x = 91.0912·log(y) -54.8424 . . . . . approximate expression
