Pretty easy. Really thirty seven. two.
Answer:
∠DFE ≅ ∠DFG
Step-by-step explanation:
we know that
Triangles are congruent by SAS, if any pair of corresponding sides and their included angles are equal in both triangles
In this problem we have that
The pair of corresponding sides that are equal are
EF=GF and DF (is the same side for both triangles)
The included angle are ∠DFE and ∠DFG
therefore
The additional information needed to prove that triangles DEF and DGF are congruent by SAS is that angles ∠DFE and ∠DFG are equal
so
∠DFE ≅ ∠DFG
Answer:
<em>The area of the actual building lot is</em> 
Step-by-step explanation:
<u>Scaling</u>
The scaled rectangular building measures 7 feet by 5 feet. We know both magnitudes were scaled by a factor of 12, thus the real dimensions of the house to be built are 7*12=84 feet, and 5*12=60 feet.
The area of the actual building lot is calculated by:
The area of the actual building lot is
C I hope I’m right I’m glad to help you
Answer:
{0, 4 and -3}
Step-by-step explanation:
f(x)=x^3-x^2-12x can be factored, starting by taking out the 'x' factor:
f(x)=x^3-x^2-12x = x(x^2 - x - 12), and then by factoring the quadratic:
f(x) = x(x - 4)(x + 3) = 0
Then the zeros are {0, 4 and -3}.
