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Elis [28]
2 years ago
13

A region R in the first quadrant of the xy-plane is bounded by the curves y = x², y = 2 - x and the x-axis. Find the value of th

e following:​

Mathematics
1 answer:
lions [1.4K]2 years ago
3 0

The two curves meet in the first quadrant when

x^2 = 2-x \implies x^2 + x - 2 = (x + 2) (x - 1) = 0 \implies x=1

Then the integral in question is

\displaystyle \iint_R x \, dA = \int_0^1 \int_{x^2}^{2-x} x \, dy \, dx \\\\ ~~~~~~~~ = \int_0^1 x (2-x-x^2) \, dx \\\\ ~~~~~~~~ = \int_0^1 (2x - x^2 - x^3) \, dx = 1 - \frac13 - \frac14 = \boxed{\frac5{12}}

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I hope this helped you!

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