Answer:
The answer that is C
Step-by-step explanation:
The equation would be y=1/2x + 8 because the line touches the y-intercept at +8. The others would be incorrect as the line does not increase by a slop of 8/1 and/or is the y-intercept at -8.
Im pretty sure its b im soo sorry if im wrong.
A^2-5a = 6
a^2-5a-6 = 0
Discriminant = (-5)^2-4(1)(-6) = 49
Discriminant is positive so there are two solutions
<h3>Answer:
10000 in base 5</h3>
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Explanation:
4+1 = 5 in base 10
But in base 5, the digit "5" does not exist.
The only digits in base five are: 0, 1, 2, 3, 4
This is similar to how in base ten, the digits span from 0 to 9 with the digit "10" not being a thing (rather it's the combination of the digits "1" and "0" put together).
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Anyways let's go back to base 5.
Instead of writing 4+1 = 5, we'd write 4+1 = 10 in base 5. The first digit rolls back to a 0 and we involve a second digit of 1.
Think how 9+1 = 10 in base 10.
Similarly,
44+1 = 100 in base 5
444+1 = 1000 in base 5
4444+1 = 10000 in base 5
and so on.
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Here are the first few numbers in base 5, when counting up by 1 each time.
0, 1, 2, 3, 4,
10, 11, 12, 13, 14,
20, 21, 22, 23, 24,
30, 31, 32, 33, 34,
40, 41, 42, 43, 44,
100, 101, 102, 103, ...
Notice each new row is when the pattern changes from what someone would expect in base 10. This is solely because the digit "5" isn't available in base 5.
