Answer:
1) -10^3 (-10 to the power of 3)
2) r^5 (pie to the power of 5)
3) 1/2^2 + x^3 (1/2 to the power of 2 + x to the power of 3)
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now
2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4
At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.
Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.
For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196
No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.
So x^2 = -4 has no real solutions. Taking the square root of both sides leads to
x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values
The question is asking you which shape is the same shape as the shape displayed with the question. The shape could be bigger, smaller, flipped around, or any other different way, but it has to be the same shape.
The answer is B.
The reason why B is your answer because the shape is the same, but it's just that it is smaller. The shapes scale is just smaller, but it's still the same shape. and flipped around.
Answer:
i believe so, 3k3 is just 3k to the third power so i think theyd be like terms still
Answer:
a. OM is congruent to ON.
Step-by-step explanation:
To use the HL Theorem, you must have a congruent hypotenuse and a congruent leg. In this case, you have two congruent hypotenuses. You just need to find two congruent legs.
a. OM is congruent to ON. This says that two legs are congruent, so this is your answer.
b. LM is congruent to ML. This does not help as it is saying a segment is the same as the same segment.
c. and d. Both of these use angle measurements, which does not help with the HL Theorem.
Hope this helps!
