All categories

2 years ago

|x+6| ≤ 8 Find the solution set?

Mathematics

1 answer:

sdas [7]2 years ago

6 0

<h3>Answer: -14 ≤ x ≤ 2</h3>

Work Shown:

|x+6| ≤ 8

-8 ≤ x+6 ≤ 8

-8-6 ≤ x+6-6 ≤ 8-6

-14 ≤ x ≤ 2

You might be interested in

An elf counted 12 small holiday sweaters, 34 medium holiday sweaters, and 27 large holiday sweaters on the store shelves. She al

mariarad [96]

Answer:

What is the question?

Step-by-step explanation:

7 0

3 years ago

A line passes through the point (-9,3) and has a slope of -2/3?

saveliy_v [14]

The point-slope form:

$y-y_1=m(x-x_1)$

We have the slope m = -2/3 and the point (-9, 3). Substitute:

$y-3=-\dfrac{2}{3}(x-(-9))$

$y-3=-\dfrac{2}{3}(x+9)$ <em>use distributive property</em>

$y-3=-\dfrac{2}{3}x-\dfrac{2}{3}\cdot9$

$y-3=-\dfrac{2}{3}x-(2)(3)$

$y-3=-\dfrac{2}{3}x-6$ <em>add 3 to both sides</em>

$\boxed{y=-\dfrac{2}{3}x-3}$

5 0

3 years ago

The center of a circle is at (−3, 1) and its radius is 9.

pickupchik [31]

Answer:

Sorry but the correct answer is (x+3)2+(y−1)2=81

Step-by-step explanation:

Because the radius squared is the answer of the equation

4 0

3 years ago

Please answer CORRECTLY !! Will mark brainliest !!!!!

Karolina [17]

Answer:

the answer is d sorry if im wrong

5 0

4 years ago

With regard to a regression-based forecast, the standard error of the estimate gives a measure of A. the variability around the

Travka [436]

Answer:

B. the variability around the regression line.

Step-by-step explanation:

The standard errors represents the distance (how sparse) the observed values fall from the regression line.

Standard errors for regression are measures of the spread of variables around the average (regression line)

The standard error is dependent on the standard deviation of the observations and the reliability of the test.

When the test is perfectly reliable, the standard error is zero and when unreliable, it is equal to the standard deviation of the observations.

8 0

3 years ago