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jekas [21]
4 years ago
12

Someone please answer these two questions

Mathematics
1 answer:
galben [10]4 years ago
7 0

Answer:

Are you dumb

Step-by-step explanation:

Stupid or dumb

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Write in standard notation 6.12 x 10 to the 3rd power
Gemiola [76]
First, we find out what 10^3 is.
10 * 10 * 10 is 1,000

Now take 1000 and multiply that by 6.12.

1000 * 6.12 = 6120

Your answer would be 6120.

 Hope this helps!

3 0
4 years ago
Citizens would like a new form of public transportation in their city. who would the address regarding this request?
Amiraneli [1.4K]
State represent................
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3 years ago
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The sum of two number is 6. Twice the first number added to three times the second number is 10. Write a system of equations and
seropon [69]

Answer:

4 and 2 are the required numbers which satisfies the given equations

Step-by-step explanation:

Let the two numbers be x and y

According to the first condition

their is is 6

which is

x + y =6                ........................(i)

Now according to second condition

twice the first number i.e. 2x added to three time the second number i.e. 3y is 10

in form of equation it could be written as

2x + 3y = 10           ........................(ii)

Now from first equation we have

x + y =6

subtracting y from both sides

x = 6 - y                    .....................(iii)

Now putting this value of x in equation (ii)

equation (ii) is

2x + 3y = 10

Putting the value gives

2(6-y)+3y = 10

opening the brackets

12 - 2y + 3y = 10

12 - y = 10

subtracting 12 from both sides

12 - y -12 = 10 -12

it becomes

- y = -2

multiplying both sides by (-1)

it becomes

(-1)(-y) = (-2) * (-1)

y = 2

Now we got the value of y put it in equation iii which is

x = 6 -y

putting the value

x = 6 - 2

x = 4

So the two numbers are x = 4 and y = 2

3 0
3 years ago
What Is the x intercept in 7x-2y=4
JulijaS [17]
(4/7,0) is the x intercept
4 0
3 years ago
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How do you solve this?
lutik1710 [3]

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{8^?}{8^3}=\cfrac{1}{8^8}\implies \cfrac{8^?}{8^3}=8^{-8}\implies 8^?=8^3\cdot 8^{-8}\implies 8^?=8^{3-8}\implies 8^?=8^{-5}


\bf \begin{array}{llll} \textit{if the bases are the same, for}\\ \textit{the equation to be true, the}\\ \textit{exponents must also be the same} \end{array}~\hspace{5em}?=-5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{1}{r^3}=r^{-7}\cdot r^?\implies r^{-3}=r^{-7+?}\implies \stackrel{\textit{bases are the same, so are the exponents}}{-3=-7+?\implies 4=?}

7 0
3 years ago
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