Question

20 years ago, father's age was 5 times his son's age. Now his age is 10 years more than twice his son's present age. Find their present ages. ​

Answer 1

Step-by-step explanation:

x = father's age now

y = son's age now

x = 2y + 10

x - 20 = 5(y - 20) = 5y - 100

using the first in the second equation :

2y + 10 - 20 = 5y - 100

-10 = 3y - 100

90 = 3y

y = 30

x = 2y + 10 = 2×30 + 10 = 60 + 10 = 70

the father is now 70 years old, the son now 30 years old.