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SashulF [63]
2 years ago
9

What is the slope of the line through (-9,6)(−9,6)left parenthesis, minus, 9, comma, 6, right parenthesis and (-6,-9)(−6,−9)left

parenthesis, minus, 6, comma, minus, 9, right parenthesis?
Mathematics
1 answer:
uranmaximum [27]2 years ago
6 0

Answer:

Step-by-step explanation:

Slope of line through (-9,6) and (-6,-9) = (-9 - 6)/(-6 - (-9)) = (-15)/(3) = -5

point-slope equation for line of slope -5 that passes through (-9,6):

y-6 = -5(x+9)

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Since all sides of the square are equal, therefore area of square can be calculated using the following rule:
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therefore,
the length of each side is sqrt(200) = 14.14 ft
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Sixty people purchase raffle tickets. Three winning tickets are selected at random. If each prize is $3000, in how many differen
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Answer:^{60}C_{3} ways.

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^{n}C_{k} is the number of ways in which k distinct objects are selected from a pile of n distinct objects.

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So,n=60.

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So,k=3.

So,the answer is ^{60}C_{3} ways.

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Factor as the product of two binomials <br> X^2 +8x +12 = ?
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Read 2 more answers
When a scientist conducted a genetics experiments with peas, one sample of offspring consisted of 943 peas, with 717 of them hav
pshichka [43]

Using the normal approximation to the binomial distribution, it is found that:

a) 0.242 = 24.2% probability of getting 717 or more peas with red flowers.

b) Since Z < 2, 717 peas with red flowers is not significantly high.

c) Since 717 peas with red flowers is not a significantly high result, we cannot conclude that the scientist's assumption is wrong.

For each pea, there are only two possible outcomes. Either they have a red flower, or they do not. The probability of a pea having a red flower is independent of any other pea, which means that the binomial distribution is used to solve this question.

Binomial distribution:

Probability of x successes on n trials, with p probability.

Normal distribution:

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • If Z > 2, the result is considered <u>significantly high</u>.

If np \geq 10 and n(1-p) \geq 10, the binomial distribution can be approximated to the normal with:

\mu = np

\sigma = \sqrt{np(1-p)}

In this problem:

  • 943 peas, thus, n = 943
  • 3/4 probability of being red, thus p = \frac{3}{4} = 0.75.

Applying the approximation:

\mu = np = 943(0.75) = 707.25

\sigma = \sqrt{np(1-p)} = \sqrt{943(0.75)(0.25)} = 13.297

Item a:

Using continuity correction, this probability is P(X \geq 717 - 0.5) = P(X \geq 716.5), which is <u>1 subtracted by the p-value of Z when X = 716.5</u>.

Then:

Z = \frac{X - \mu}{\sigma}

Z = \frac{716.5 - 707.25}{13.297}

Z = 0.7

Z = 0.7 has a p-value of 0.758.

1 - 0.758 = 0.242

0.242 = 24.2% probability of getting 717 or more peas with red flowers.

Item b:

Since Z < 2, 717 peas with red flowers is not significantly high.

Item c:

Since 717 peas with red flowers is not a significantly high result, we cannot conclude that the scientist's assumption is wrong.

A similar problem is given at brainly.com/question/25212369

6 0
3 years ago
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