The function f(x) = (6/120) x + 40
= 0.05x + 40 where x is the excess mileage over 100
If we drive it for 300 miles x will be 300-100 = 200
so cost will be 0.05*200 + 40
= 10+40 = $50 answer
Answer: The width of the class interval would be 6.
Step-by-step explanation:
Formula to find the class width :
Given : The range of a distribution were 89 .i.e. Range = 89
The approximate number of class intervals = 14
Then, the width of the class interval would be
[Round to the nearest integer.]
Hence, the width of the class interval would be 6.
1.
which is further simplified to
which is 20.
2.