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3 years ago

ONLY NUMBER 1 please help

Mathematics

2 answers:

yan [13]3 years ago

5 0

Answer:

Just to be on the safe side the first #1 is 31.5 and the second #1 is 57.82

LUCKY_DIMON [66]3 years ago

5 0

Answer:

90 cm^2

Step-by-step explanation:

A=10 (9)

A= 90 cm^2

^2= squared

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50 points for who ever helps 5√x 14 simplify

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Answer:

5√14x

Step-by-step explanation:

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3 years ago

RectangleABCD has vertices at A(– 3, 1),B(– 2, – 1),C(2, 1), andD(1, 3). What is the area, in square units, of this rectangle? A

Anna [14]

Answer:

Option A. $10\ units^{2}$

Step-by-step explanation:

we know that

The area of the rectangle is equal to

A=LW

where

L is the length of rectangle

W is the width of rectangle

we have

$A(-3,1),B(-2,-1),C(2,1),D(1,3)$

Plot the vertices

see the attached figure

L=AD=BC

W=AB=DC

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AD

$A(-3,1),D(1,3)$

substitute in the formula

$AD=\sqrt{(3-1)^{2}+(1+3)^{2}}$

$AD=\sqrt{(2)^{2}+(4)^{2}}$

$AD=\sqrt{20}$

$AD=2\sqrt{5}\ units$

Find the distance AB

$A(-3,1),B(-2,-1)$

substitute in the formula

$AB=\sqrt{(-1-1)^{2}+(-2+3)^{2}}$

$AB=\sqrt{(-2)^{2}+(1)^{2}}$

$AB=\sqrt{5}$

$AB=\sqrt{5}\ units$

Find the area

$A=(2\sqrt{5})*(\sqrt{5})=10\ units^{2}$

4 0

3 years ago

FP!!!!!!!!!!!!!!!!!!! if ur up ( 10 x 8 ) + 150

taurus [48]

Answer:

220

Step-by-step explanation:

first we have by Bracket of BODMAS rule then we have to multiply 10 *8 = 80

first we have by Bracket of BODMAS rule then we have to multiply 10 *8 = 80then we have to open bracket 80 +150

first we have by Bracket of BODMAS rule then we have to multiply 10 *8 = 80then we have to open bracket 80 +150 = 220

(10*8) +15

Solution

Solution= (80) +150

Solution= (80) +150= 80+150

Solution= (80) +150= 80+150=. 220

Solution= (80) +150= 80+150=. 220

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