Can you give me a example on how to do this that would be really helpfull

Mathematics

1 answer:

Rom4ik [11]3 years ago

6 0

We'll do the first one. I can't read the variable, but it looks like a $\theta$ so that's what I'll use, but it doesn't matter.

First, get the variable by itself:

$\theta$

You get that before you multiply each side by two.

Now, you color the line so that all values that are less than 6 are shaded, so you put an open circle at 6 since it's not included and then you shade everything to the left.

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An angle is five times its supplement. Find both angles.

noname [10]

The measure of the smaller angle is 30 degrees.
The measure of the larger angle is 150 degrees.

What I did:
supplementary angle=180 degrees.
<span>An angle is five times its supplement=180/6=
30
30*5=150
150+30=180

</span>

5 0

3 years ago

Which equation represents a line that has the slope 1/3 and passes through the point (-2,1)

goldenfox [79]

Answer:

y - 1 = (1/3)(x + 2)

Step-by-step explanation:

Here m = 1/3 and (-2, 1) is a point on the line. The appropriate equation is

y - k = m(x - h), where (h, k) is the pt on the line.

Subbing the known values, we get:

y - 1 = (1/3)(x + 2)

3 0

3 years ago

1. Triangle ABC is similar to triangle JKL.

Fittoniya [83]

1. It's all about pattern matching, as a lot of math is.
Letter A corresponds to letter J, as both are first in the names of their respective triangles.
Letter B corresponds to letter K, as both are second in the triangle names. Likewise, letter C corresponds to letter L, as both are last.

Realizing this, it should not be too much of a stretch to see
∠B ⇒ ∠K
∠C ⇒ ∠L
AC ⇒ JL
BC ⇒ KL

2. Same deal. Match the patterns. Here, you're counting rings in the angle marks.
1 ⇒ 1, so A ⇒ R
2 ⇒ 2, so B ⇒ Q
since the figures are reportedly similar, you can continue in the same order to finish.
ABCD ~ RQPS

3. The marked triangles cannot be similar. There are a number of ways to figure this. Basically, you want the ratios of sides to be the same for any similar triangles.

Here, you can eliminate the marked ones because the short side is too short relative to the others. (The average of the other two sides is double the short side in the similar triangles.)