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olasank [31]
2 years ago
12

Can you give me a example on how to do this that would be really helpfull

Mathematics
1 answer:
Rom4ik [11]2 years ago
6 0
We'll do the first one.  I can't read the variable, but it looks like a \theta so that's what I'll use, but it doesn't matter.

First, get the variable by itself:

\theta

You get that before you multiply each side by two.  

 Now, you color the line so that all values that are less than 6 are shaded, so you put an open circle at 6 since it's not included and then you shade everything to the left.
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Find the greatest maximum y-value of the following equation:
KatRina [158]
A quick way to do this is by recalling the fact that -1\le\cos x\le1, so the largest value that \cos ax alone (for any real value of a) can take on is 1.

This means -3\le3\cos2x\le3, and so 1\le3\cos2x+4\le7.

So the maximum value of this function is 7.
5 0
3 years ago
PLEASE PELASE PLEASE HELP ME
V125BC [204]

Answer:

In ∆ABC AND ∆DEF

ABC=DEF...........each 90°

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2 years ago
A mountain climber ascends 800 feet per hour from his original
navik [9.2K]

Answer:

4,800

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Just multiply 800 x 6, which gets 6,800. Then, get 11,600 and subtract 6,800 from it. You'll get 4,800.

7 0
3 years ago
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Feliz [49]

Answer:

i may be wroung but it should be 90

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
At 4:00p.m the temperature was 90F after this point the temperature dropped 1.5F per hour until sunrise the next morning write a
irina [24]

Answer:

90t-21t=69t

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4:00pm to 6:00 am is 14 hours. 14 x 1.5 is in fact 21 which means the temperature dropped 21 degrees in those 14 hours.

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3 years ago
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