Question

If h(-8), find 1/3*h(x) = x^2-5x+7

Answer 1

The value is 333

How to determine the function

From the information given, we have:

• x = - 8
• 1/3*h(x) = x^2-5x+7

Now, let's substitute the value of 'x' in the function:

1/3*h(x) = x^2-5x+7

1/ 3 × h(-8) = ( - 8)² - 5 ( -8) + 7

Make 'h ( -8)' the subject of formula

h ( -8) = $\frac{( -8)^2 - 5(-8) + 7}{1/ 3}$

h ( -8) = $\frac{64 + 40+ 7 }{1/ 3}$

Take the sum of the numerator

h ( -8) = $\frac{111}{1/3}$

Take the inverse of the denominator and multiply

h ( -8) = 111 × 3/ 1

h ( -8) = 333

We can see that through the substitute of the value of x as - 8, we get 333

Thus, the value is 333

Learn more about algebraic expressions here:

brainly.com/question/723406

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