If h(-8), find 1/3*h(x) = x^2-5x+7
1 answer:
The value is 333
<h3>How to determine the function</h3>From the information given, we have:
- x = - 8
- 1/3*h(x) = x^2-5x+7
Now, let's substitute the value of 'x' in the function:
1/3*h(x) = x^2-5x+7
1/ 3 × h(-8) = ( - 8)² - 5 ( -8) + 7
Make 'h ( -8)' the subject of formula
h ( -8) =
h ( -8) =
Take the sum of the numerator
h ( -8) =
Take the inverse of the denominator and multiply
h ( -8) = 111 × 3/ 1
h ( -8) = 333
We can see that through the substitute of the value of x as - 8, we get 333
Thus, the value is 333
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Answer:
(a) The probability that the store’s revenues were at least $9,000 is 0.0233.
(b) The revenue of the store on the worst 1% of such days is $7,631.57.
Step-by-step explanation:
According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.
Then, the mean of the distribution of the sum of values of X is given by,
And the standard deviation of the distribution of the sum of values of X is given by,
It is provided that:
As the sample size is quite large, i.e. <em>n</em> = 310 > 30, the central limit theorem can be applied to approximate the sampling distribution of the store’s revenues for Sundays by a normal distribution.
(a)
Compute the probability that the store’s revenues were at least $9,000 as follows:
Thus, the probability that the store’s revenues were at least $9,000 is 0.0233.
(b)
Let <em>s</em> denote the revenue of the store on the worst 1% of such days.
Then, P (S < s) = 0.01.
The corresponding <em>z-</em>value is, -2.33.
Compute the value of <em>s</em> as follows:
Thus, the revenue of the store on the worst 1% of such days is $7,631.57.