Question

the length of the sides of a square are initially 0 cm and increase at a constant rate of 11 cm per second. suppose the function f determines the area of the square (in cm2) given a number of seconds, t , since the square started growing. write a function formula for f .

Answer 1

The function of the area of the square is A(t)=121$t^{2}$

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

$\frac{dx}{dt} =$ 11 $\frac{cm}{sec}$

⇒x=11t

Area of square=$(length of side)^{2}$

Area of square=$(11t)^{2}${as the length of side is 11t}{varies by time}

Area of square=121$t^{2}$

Therefore,The function of the area of the square is A(t)=121$t^{2}$

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Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

$\frac{dx}{dt} =$ 11 $\frac{cm}{sec}$

⇒x=11t

Area of square=$(length of side)^{2}$

Area of square=$(11t)^{2}${as the length of side is 11t}{varies by time}

Area of square=121$t^{2}$

Therefore,The function of the area of the square is A(t)=121$t^{2}$

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