A data point that is insignificantly larger or smaller than other values. for example...
2 3 6 1 129, 129 is an outlier because it is insignificantly larger than the others

7 0

3 years ago

Hence, write as single frachon in its lowest terms. 2/y-1 - 4/y^2-1

sleet_krkn [62]

Answer:

$\frac{2}{y+1}$

Step-by-step explanation:

Factorise the denominator of the second fraction

y² - 1 = (y - 1)(y + 1) ← difference of squares

To obtain a common denominator

multiply numerator/ denominator of first fraction by (y + 1)

= $\frac{2(y+1)}{(y-1)(y+1)}$ - $\frac{4}{(y-1)(y+1)}$ ← subtract numerators leaving the common denominator

= $\frac{2y+2-4}{(y-1)(y+1)}$

= $\frac{2y-2}{(y-1)(y+1)}$

= $\frac{2(y-1)}{(y-1)(y+1)}$ ← cancel common factor (y - 1) on numerator/denominator

= $\frac{2}{y+1}$

6 0

3 years ago

How do I find the orthocenter of the triangle with these coordinates (8,10) (5,-10) (0,0)

WINSTONCH [101]

Find the equation of 2 of the line segment, then find the perpendicular lines to them, then solve for x by making the perpendicular equations equal

7 0

3 years ago

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