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yarga [219]
3 years ago
10

X=8 f(x)=|x| f(8)=?help me please?

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
4 0
Is there not more to this problem? maybe thats the final answers
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What is the answer to this question
almond37 [142]

Answer:

C. 24 1/4

Step-by-step explanation:

You turn both the lowest and the highest values into improper fractions and subtract the numerators then turn it back into a mixed fraction.

7 0
3 years ago
Use the substitution method to solve the system of equations. Choose the correct ordered pair.
motikmotik
Ur gonna have to pick an equation and solve for a variable.

2x - 2y = 6
2x = 2y + 6 ...divide everything by 2 because u want x by itself
x = y + 3

now we sub y + 3 in for x in the other equation
14x - 2y = 78
14(y + 3) - 2y = 78...distribute thru the parenthesis
14y + 42 - 2y = 78...subtract 42 from both sides, cancelling the 42 on the left
        -42          -42
-----------------------
14y - 2y = 36 ...simplify
12y = 36...divide by 12 on both sides, cancelling out the 12 on the left
y = 36/12
y = 3

now , we already know that x = y + 3...and we know y = 3...so sub in 3 for y and solve for x
x = y + 3
x = 3 + 3
x = 6

solution is (6,3)

it is always a good idea to check ur answer by subbing it into one or both of the equations to see if it is correct
2x - 2y = 6......(6,3)...x = 6 and y = 3
2(6) - 2(3) = 6
12 - 6 = 6
6 = 6 (correct)

so yes, ur solution is (6,3)
4 0
3 years ago
Read 2 more answers
What's the ratio of 75 to 80?
oksano4ka [1.4K]

Answer:

75:80   OR    15:16

Step-by-step explanation:

7 0
3 years ago
33 1/3 of 21 (finding the percent of a number)
iragen [17]
<span>33% of 21=6.93 i think this is the answer</span>
5 0
3 years ago
GEOMETRY!!!! K' (6,5) is the image of K after a reflection in the line y=2. what are the coordinates of K
frutty [35]

Given:

The coordinates of point K' are (6,5).

K' is the image of K after a reflection in the line y=2.

To find:

The coordinates of point K.

Solution:

Let the coordinates of point K are (a,b).

If a figure is reflected over the line y=2, then

(x,y)\to (x,2(2)-y)

(x,y)\to (x,4-y)

Using this formula, the coordinates of image of K are

K(a,b)\to K'(a,4-b)

The coordinates of point K' are (6,5).

K'(a,4-b)=K'(6,5)

On comparing both sides, we get

a=6\text{ and }4-b=5

a=6\text{ and }-b=5-4

a=6\text{ and }-b=1

a=6\text{ and }b=-1

Therefore, the coordinates of point K are (6,-1).

3 0
3 years ago
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