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yarga [219]
3 years ago
10

X=8 f(x)=|x| f(8)=?help me please?

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
4 0
Is there not more to this problem? maybe thats the final answers
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The coordinate plane shows the floor plan for a swimming pool. What is the area of the pool’s border?"
emmasim [6.3K]
<span>A = Area
L= Length = 15
W + widith = 10
A = 150
The pool area is L = 10
w= 5
A= 50
So the area of the perimeter = 100 square meters</span>
5 0
3 years ago
Read 2 more answers
A grocery store’s receipts show that Sunday customer purchases have a skewed distribution with a mean of 27$ and a standard devi
34kurt

Answer:

(a) The probability that the store’s revenues were at least $9,000 is 0.0233.

(b) The revenue of the store on the worst 1% of such days is $7,631.57.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{X}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

\sigma_{X}=\sqrt{n}\sigma

It is provided that:

\mu=\$27\\\sigma=\$18\\n=310

As the sample size is quite large, i.e. <em>n</em> = 310 > 30, the central limit theorem can be applied to approximate the sampling distribution of the store’s revenues for Sundays by a normal distribution.

(a)

Compute the probability that the store’s revenues were at least $9,000 as follows:

P(S\geq 9000)=P(\frac{S-\mu_{X}}{\sigma_{X}}\geq \frac{9000-(27\times310)}{\sqrt{310}\times 18})\\\\=P(Z\geq 1.99)\\\\=1-P(Z

Thus, the probability that the store’s revenues were at least $9,000 is 0.0233.

(b)

Let <em>s</em> denote the revenue of the store on the worst 1% of such days.

Then, P (S < s) = 0.01.

The corresponding <em>z-</em>value is, -2.33.

Compute the value of <em>s</em> as follows:

z=\frac{s-\mu_{X}}{\sigma_{X}}\\\\-2.33=\frac{s-8370}{316.923}\\\\s=8370-(2.33\times 316.923)\\\\s=7631.56941\\\\s\approx \$7,631.57

Thus, the revenue of the store on the worst 1% of such days is $7,631.57.

5 0
2 years ago
1. What is the percent as a decimal? 73% *<br> O<br> 0.73<br> 7.3<br> 0.0073<br> Ο Ο<br> 730
kotegsom [21]

Answer:

0.73

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
I need help <br> 860 pounds + 4 gallons
Volgvan

Answer:

893.3816

Step-by-step explanation:

pretty sure your converting gallons into pounds and if that's the case 4 gallons is 33.3816 lbs so I added 860 + 33.38.16 then I got 893.3816

4 0
3 years ago
How do i find an I Q R ?
Scrat [10]

Answer:

Sorry if this doesn't help:

Step-by-step explanation:

1, Order the data from least to greatest.

2, Find the median.

3, Calculate the median of both the lower and upper half of the data.

4, The IQR is the difference between the upper and lower medians.

Good luck!

3 0
3 years ago
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