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Black_prince [1.1K]

2 years ago

12

Supposed you write and solve an equation to determine the amount of money m you have in your bank account after several weeks. Y

ou find that m=-36. What does this solution mean?

2 answers:

vodomira [7]2 years ago

6 0

Answer:

this means you have find the m=36 first after that you will have to change 36 to currency

TiliK225 [7]2 years ago

3 0

The meaning of the solution, m=-36 as given in the task content is; that one owes the bank 36.

<h3>What does the solution as given in the task content mean?</h3>

It follows from the task content that the solution given for m is; m = -36.

Since, m represents the amount of money in the bank account after several weeks, it follows that one not only has nothing left in the account, but, also owes the bank 36.

Read more on negative numbers;

brainly.com/question/1647835

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Annette [7]

Answer:

is awnser is 1

Step-by-step explanation:

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3 years ago

What is the equation of a line passing through the point (1,2) and parallel to the line y=3x+2?

vova2212 [387]

Y=3x-1 have a great day!!

3 0

3 years ago

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Two ships are sailing parallel to each other. The path of one ship is represented on a coordinate plane as the line y = –1/3x +

AfilCa [17]

(0,6)

parallel lines have the same slope (-1/3 in this case) so the equations will have the same slope

the line y=-1/3x+6 passes through (3,5)
any point on that line is a valid answer but for an example (0,6) which is the y-intercept

4 0

4 years ago

charle [14.2K]

Answer:

56 + 23 + (-5)

you want to expand the bracket first

23 + (-5)

23-5 = 18

56 + 18 = 74

a) 74

6 + 24 + (-2)

24 - 2= 22

6 + 22 = 28

b) 28

3 + 7 + (-42)

7 - 42 = -35

3 - 35 = -32

c)-32

( 8 + 1 ) + (-3)

+(-3) = -3

9 - 3 = 6

d)6

( 7 + 10 ) + ( 3 + 1 )

17 + 4 = 21

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59 + 2+ (-6)

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59-4

55

f)55

41 + ( -89)

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8 0

3 years ago

Find all solutions in the interval [0, 2π). <br> 2 sin2x = sin x

tester [92]

Answer:

The solutions on the given interval are :

$0$

$\pi$

$\cos^{-1}(\frac{1}{4})$

$-\cos^{-1}(\frac{1}{4})+2\pi$

Step-by-step explanation:

We will need the double angle identity $\sin(2x)=2\sin(x)\cos(x)$ .

Let's begin:

$2\sin(2x)=\sin(x)$

Use double angle identity mentioned on left hand side:

$2\cdot 2\sin(x)\cos(x)=\sin(x)$

Simplify a little bit on left side:

$4\sin(x)\cos(x)=\sin(x)$

Subtract $\sin(x)$ on both sides:

$4\sin(x)\cos(x)-\sin(x)=0$

Factor left hand side:

$\sin(x)[4\cos(x)-1]=0$

Set both factors equal to 0 because at least of them has to be 0 in order for the equation to be true:

$\sin(x)=0 \text{ or } 4\cos(x)-1=0$

The first is easy what angles $\theta$ are $y$ -coordinates on the unit circle 0. That happens at $0$ and $\pi$ on the given range of $x$ (this $x$ is not be confused with the $x$ -coordinate).

Now let's look at the second equation:

$4\cos(x)-1=0$

Isolate $\cos(x)$ .

Add 1 on both sides:

$4 \cos(x)=1$

Divide both sides by 4:

$\cos(x)=\frac{1}{4}$

This is not as easy as finding on the unit circle.

We know $\arccos( )$ will render us a value between $0$ and $2\pi$ .

So one solution on the given interval for x is $x=\cos^{-1}(\frac{1}{4})$ .

We know cosine function is even.

So an equivalent equation is:

$\cos(-x)=\frac{1}{4}$

Apply $\cos^{-1}$ to both sides:

$-x=\cos^{-1}(\frac{1}{4})$

Multiply both sides by -1:

$x=-\cos^{-1}(\frac{1}{4})$

This going to be negative in the 4th quadrant but if we wrap around the unit circle, $2\pi$ , we will get an answer between $0$ and $2\pi$ .

So the solutions on the given interval are :

$0$

$\pi$

$\cos^{-1}(\frac{1}{4})$

$-\cos^{-1}(\frac{1}{4})+2\pi$

5 0

3 years ago