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enot [183]
2 years ago
13

Points A and B have coordinates A(-4, 2) and B(3,-6). Find the coordinates of point P, the weighted average of points A and B, i

n which point A
has a weight of 2 and point 8 has a weight of 5.
A) (-2,-²)
B) (-2)
C) (1,-)
D) (1,-13)

Mathematics
1 answer:
lys-0071 [83]2 years ago
7 0

Answer:

  C)  P(1, -26/7)

Step-by-step explanation:

You want the weighted average of A(-4, 2) and B(3,-6) using weights 2 and 5, respectively.

<h3>Weighted average</h3>

Each of the values is multiplied by the corresponding weight, and the sum of those products is divided by the total of the weights to obtain the weighted average.

  P = (2A +5B)/(2+5)

  P = (2(-4, 2) +5(3, -6))/7 = (-8 +15, 4 -30)/7 = (7, -26)/7

  P = (1, -26/7)

The coordinates of P are (1, -26/7).

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Calculate the distance between the points M=(-1, -2) and C=(-9, 2) in the coordinate plane.
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Answer:

nearest hundredth 8.944

Step-by-step explanation:

d = √((x2-x1)2 + (y2-y1)2)

Step by step procedure:

Find the difference between coordinates:

(x2-x1) = (-9 - -1) = -8

(y2-y1) = (2 - -2) = 4

Square the results and sum them up:

(-8)2 + (4)2 = 64 + 16 = 80

Now Find the square root and that's your result:

Exact solution: √80 = 4√5

Approximate solution: 8.944

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