8 times 8 times 7 please help

A building that is 750 feet tall casts a shadow the is 111 feet long. find the angle of of elevation, in degrees, to the sun.

stepan [7]

Imagine the shadow and the building height forms a right angle triangle;

We know the height and the shadow make up the "legs" of the triangle,

a²+b²=c²
(750)²+(111)²=c²
562500+12321=c²
574821=c²
c=√574821
c=758.169 ≈ 758.2 ft

Hope I helped :)

7 0

3 years ago

PLEASE HELP!!! Two towns are 1100 miles apart. A group of hikers starts from each town and walks down the trail toward each othe

Vinvika [58]

Answer:

2.54 miles/hr

2.04 miles/hr

Step-by-step explanation:

Given: Distance between the two towns = 1100 miles

Difference between speeds = $\frac{1}{2}$ miles/hr

Total time when they meet = 240 hours

To find:

Let distance traveled by first group = $x$ miles.

Now, the distance traveled by second group = (1100- $x$ ) miles/hr

The relation between Speed, Time and Distance is given as:

$\text{Speed =} \dfrac{\text{Distance}}{\text{Time}}$

Let speed of first group = $S_1$

$S_1 = \dfrac{x}{240}$

Let speed of second group = $S_2$

$S_2 = \dfrac{1100-x}{240}$

As per question, $S_1$ = $S_2$ + $\frac{1}{2}$

$\dfrac{x}{240} = \dfrac{1100-x}{240} + \dfrac{1}{2}\\\Rightarrow \dfrac{x}{240} - \dfrac{1100-x}{240} = \dfrac{1}{2}\\\Rightarrow \dfrac{x-1100+x}{240} = \dfrac{1}{2}\\\Rightarrow 2x - 1100 = 120\\\Rightarrow 2x = 1220\\\Rightarrow x = 610 ft$

Now,

$S_1 = \dfrac{x}{240}$

Putting value of $x$ :

$S_1 = \dfrac{610}{240}\\\Rightarrow S_1 = 2.54\ miles/hr$

Similarly, putting value of $x$ in $S_2$ :

$S_2 = \dfrac{1100-610}{240}\\\Rightarrow S_2=\dfrac{490}{240}\\\Rightarrow S_2 = 2.04\ miles/hr$

8 0

3 years ago

You have inherited land that was purchased for $25,000 in 1970. The value of the land has appreciated by

Darina [25.2K]

Answer:

Future value of land = 25,000[1.04]³⁰

Future value of land = $81,084 (Approx.)

Step-by-step explanation:

Given:

Purchase cost of land in 1970 = $25,000

Application rate = 4% per year

Find:

Price of land in 2000

Computation:

Number of year = 2000 - 1970 = 30 year

Future value of land = [Purchase cost of land][1+Application rate]ⁿ

F = P[1+r]ⁿ

Future value of land = 25,000[1+4%]³⁰

Future value of land = 25,000[1+0.04]³⁰

Future value of land = 25,000[1.04]³⁰

Future value of land = 25,000[3.24339]

Future value of land = 81,084.75

Future value of land = $81,084 (Approx.)

5 0

3 years ago

Mrs. Rouse has three times as many gladiolus as Mrs. Leal together they have 128 gladiolus write the system of equations for thi

natka813 [3]

R = # of Gladiolus Mrs. Rouse has
L = # of gladiolus Mrs. Leal has

R = 3L
R+L = 128

Solution for number of Gladiolus each has

3L + L = 128

4L = 128

L = 32

R = 3(32) = 96

3 0

3 years ago

Find the center and radius of the circle whose equation is x 2 + y 2 - 6x - 2y + 4 = 0

elena-s [515]

Answer:

${ \tt{ {x}^{2} + {y}^{2} - 6x - 2y + 4 = 0 }}$