Solve for x:(2 x + 3)/3 - 1 = 10
Put each term in (2 x + 3)/3 - 1 over the common denominator 3: (2 x + 3)/3 - 1 = (2 x + 3)/3 - (3)/3:(2 x + 3)/3 - (3)/3 = 10
(2 x + 3)/3 - (3)/3 = ((2 x + 3) - 3)/3:(-3 + 3 + 2 x)/3 = 10
Add like terms. 3 - 3 = 0:(2 x)/3 = 10
Multiply both sides of (2 x)/3 = 10 by 3/2:(3×2 x)/(2×3) = (3×10)/2
(3×10)/2 = (3×10)/2:(3×2 x)/(2×3) = (3×10)/2
(3×2 x)/(2×3) = (2×3)/(2×3)×x = x:x = (3×10)/2
10/2 = (2×5)/2 = 5:x = 3×5
3×5 = 15:Answer: x = 15
sinx-1 evaluates to s-1
<span>tanx+secx evaluates to t+sHere, you are trying to multiply two binomials together. To work this problem, we'll use the "F.O.I.L." method. First, we'll multiply the two First terms, the s and t together. Second, we'll multiply the two Outer terms, the s and s together. Third, we'll multiply the two Inner terms, the -1 and t together. Lastly, we'll multiply the two Last terms, the -1 and s together. The correct answer is st + s^2 - t - sThank you for posting your question. I hope that this answer helped you. Let me know if you need more help.
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Yes you’re almost there the answer is negative 9
