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Scrat [10]
1 year ago
14

A company offers each of its 80 workers either a desktop computer that costs $900 or a laptop that costs $1550. Write and simpli

fy an expression for the cost of all the computers when n workers choose desktop computers. Find the cost if 65 workers choose desktop computers.
Mathematics
1 answer:
Vesna [10]1 year ago
7 0

The simplified expression for the total cost is 124000 - 650n and the cost if 65 workers choose desktop computers is 81750

<h3>Write and simplify an expression for the cost of all the computers </h3>

The given parameters are:

Number of workers = 80

Cost of desktop = $900

Cost of laptop = $1550

If n workers choose desktop computers, then 80 - n workers choose laptop computers

So, the expression for the cost of all the computers is

Total cost = 900n + 1550 * (80 - n)

Expand

Total cost = 900n + 124000 - 1550n

Evaluate the like terms

Total cost = 124000 - 650n

Hence, the simplified expression for the total cost is 124000 - 650n

<h3>Find the cost if 65 workers choose desktop computers.</h3>

This means that n = 65.

So, we have:

Total cost = 124000 - 650* 65

Evaluate

Total cost = 81750

Hence, the cost if 65 workers choose desktop computers is 81750

Read more about expressions at:

brainly.com/question/723406

#SPJ1

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Can someone please help me
Bad White [126]

Answer:

<h2>L.A. = 384 cm²</h2><h2>S.A. = 640 cm²</h2>

Step-by-step explanation:

Lateral Area:

We have four congruent triangles with base b = 16cm and height h = 12cm.

The formula of an area of a traingle:

A_\triangle=\dfrac{bh}{2}

Substitute:

A_\triangle=\dfrac{(16)(12)}{2}=(8)(12)=96\ cm^2

L.A.=4A_\triangle=4(96)=384\ cm^2

Surface Area:

S.A.=B+L.A.

In the base we have the square with side s = 16cm. The formula of an area of a square:

A_\square=s^2

Substitute:

B=16^2=256\ cm^2

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Wich of the following equations would NOT contain the point (4,12)
nlexa [21]

Given:

The given point is (4,12).

To find:

The equation that would NOT contain the point (4,12).

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We need to check each equation for the point (4,12).

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y=-2x+20

Putting x=4, we get

y=-2(4)+20

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This equation contains the point (4,12).

In option B, the given equation is:

y=\dfrac{1}{2}x+8

Putting x=4, we get

y=\dfrac{1}{2}(4)+8

y=2+8

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This equation does not contain the point (4,12).

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y=-\dfrac{1}{2}x+14

Putting x=4, we get

y=-\dfrac{1}{2}(4)+14

y=-2+14

y=12

This equation contains the point (4,12).

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y=\dfrac{3}{4}x+9

Putting x=4, we get

y=\dfrac{3}{4}(4)+9

y=3+9

y=12

This equation contains the point (4,12).

Only the equation in option B does NOT contain the point (4,12). Therefore, the correct option is B.

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Step-by-step explanation:

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