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3 years ago

Hi help me with this too pls I can't pls

Mathematics

1 answer:

Musya8 [376]3 years ago

4 0

Answer:

1) 3(9) +15

2) 2(-5)^2 - 11

3) (-2)^3 + 13(-2)

4) 4(6)^2 -7

5) (-9)^2 - (-9) + 10

All you have to do solve

Step-by-step explanation:

Replace the x with whatever number is in the f(number)

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The parabolas defined by the equations y=-x^2-x+1 and y=2x^2-1 intersect at points (a, b) and (c, d), where c>=a. What is c-a

Fittoniya [83]

Answer:

c - a = $\frac{5}{3}$

Step-by-step explanation:

Since the parabolas intersect we can equate them, that is

2x² - 1 = - x² - x + 1 ← subtract terms on right side from terms on left side

3x² + x - 2 = 0

Consider the factors of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 2 = - 6 and sum = + 1

The factors are + 3 and - 2

Use these factors to split the x- term

3x² + 3x - 2x - 2 = 0 ( factor the first/second and third/fourth terms )

3x(x + 1) - 2(x + 1) = 0 ← factor out (x + 1) from each term

(x + 1)(3x - 2) = 0

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

3x - 2 = 0 ⇒ 3x = 2 ⇒ x = $\frac{2}{3}$

Since c > a, then

a = - 1 and c = $\frac{2}{3}$

Thus

c - a = $\frac{2}{3}$ - (- 1) = $\frac{2}{3}$ + 1 = $\frac{2}{3}$ + $\frac{3}{3}$ = $\frac{5}{3}$

3 0

3 years ago

This is due in 15 minutes pls help me lol thx

GaryK [48]

Answer:

ITS A

Step-by-step explanation:

PLZ GIVE BRAINLEIST

7 0

3 years ago

Read 2 more answers

Complete the equation of the line through (-1,6) and (7,-2)

ASHA 777 [7]

$\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{-2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{6}}}{\underset{run} {\underset{x_2}{7}-\underset{x_1}{(-1)}}}\implies \cfrac{-8}{7+1}\implies \cfrac{-8}{8}\implies -1$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{-1}[x-\stackrel{x_1}{(-1)}] \\\\\\ y-6=-(x+1)\implies y-6=-x-1\implies y=-x+5$

3 0

4 years ago

Determine the quadrant in which the terminal side of the given angle lies. -300°

Lilit [14]

Answer:

-270 to -360 degrees I quadrant

And for this case since -300° is between -270 to -360 degrees we can conclude that this angle is in the I quadrant

Step-by-step explanation:

For this case we can solve this problem taking in count the following rule when we have negative angles:

0 to -90 degrees IV quadrant

-90 to -180 degrees III quadrant

-180 to -270 degrees II quadrant

-270 to -360 degrees I quadrant

And for this case since -300° is between -270 to -360 degrees we can conclude that this angle is in the I quadrant

3 0

3 years ago

5) What three consecutive even integers have a sum of 18?

LenKa [72]

Answer: 5, 6, and 7.

Step-by-step explanation:

4 0

3 years ago

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Hi help me with this too pls I can't pls​

Hi help me with this too pls I can't pls