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2 years ago

12

Hi help me with this too pls I can't pls

1 answer:

Musya8 [376]2 years ago

4 0

Answer:

1) 3(9) +15

2) 2(-5)^2 - 11

3) (-2)^3 + 13(-2)

4) 4(6)^2 -7

5) (-9)^2 - (-9) + 10

All you have to do solve

Step-by-step explanation:

Replace the x with whatever number is in the f(number)

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Let's solve for the answer to determine if it is rational.

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2 years ago

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2 years ago

What is the equation of the line in slope-intercept form that is perpendicular to the line y = x – 2 and passes through the poin

Ostrovityanka [42]

Y= 3/4x - 2 (-2,10)= (x1,y1)
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2 years ago

Solve the Differential equation (x^2 + y^2) dx + (x^2 - xy) dy = 0

natita [175]

Answer:

$\frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C$

Step-by-step explanation:

Given differential equation,

$(x^2 + y^2) dx + (x^2 - xy) dy = 0$

$\implies \frac{dy}{dx}=-\frac{x^2 + y^2}{x^2 - xy}----(1)$

Let y = vx

Differentiating with respect to x,

$\frac{dy}{dx}=v+x\frac{dv}{dx}$

From equation (1),

$v+x\frac{dv}{dx}=-\frac{x^2 + (vx)^2}{x^2 - x(vx)}$

$v+x\frac{dv}{dx}=-\frac{x^2 + v^2x^2}{x^2 - vx^2}$

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$x\frac{dv}{dx}=\frac{1 + v^2}{v-1}-v$

$x\frac{dv}{dx}=\frac{1 + v^2-v^2+v}{v-1}$

$x\frac{dv}{dx}=\frac{v+1}{v-1}$

$\frac{v-1}{v+1}dv=\frac{1}{x}dx$

Integrating both sides,

$\int{\frac{v-1}{v+1}}dv=\int{\frac{1}{x}}dx$

$\int{\frac{v-1+1-1}{v+1}}dv=lnx + C$

$\int{1-\frac{2}{v+1}}dv=lnx + C$

$v-2ln(v+1)=lnx+C$

Now, y = vx ⇒ v = y/x

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2 years ago

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2 years ago