<h3>Answer:</h3>
A) x = 2
<h3>Explanation:</h3>
<em>Try the answers</em>
Of the offered choices, the only ones that go through the given point are ...
... x = 2
... y = -5
The latter is horizontal and parallel to y = 7, so is not the choice you want. The appropriate choice is ...
... A) x = 2
_____
<em>Figure out the answer</em>
The given line is horizontal, so the line you want is vertical—of the form ...
... x = constant
The constant must be chosen so the line will go through a point with x=2. It should be obvious that the constant must be 2.
... x = 2 is perpendicular to y = 7 and goes through (2, -5).
OK, so;
BDE and BED are congruent because the opposite sides are both congruent
To find BDE and BED you must subtract 66 degrees from 180 degrees.
You are then left with 114 as the sum of both the angles you need to find
Since they are congruent, all you need to do is divide by two
114/2=57 degrees for both BDE (a) and BED(b)
Now for angle A and C;
This is easy because they are both congruent to the first two!
So basically, all of question four is "57 degrees"
Sadly for number 5 i did not understand the question :"(
For 6 tho;
AC is parallel to DE because angle C is congruent to angle BED
All the others can be ruled out
For 7;
BD is half the length of AE, so:
4x+20=2(3x+5)
4x+20=6x+10
20=2x+10
10=2x
x=5
This means BD is 20 bc
3(5)+5
15+5
20
And AE is 40 bc
20X2=40
or...
4(5)+20
Answer:
(Hope this helps can I pls have brainlist (crown) ☺️)
Step-by-step explanation:
In pic
Answer: The p(success) = 0.6
Your question is a little unclear, but I believe you are asking about the probability that at least one of the trials in the experiment were successful.
If that is the case, you simply have to add the probability of 1 success with the probability of 2 successes.
That is 0.48 + 0.16 = 0.64
Rounding our answer to one decimal place gives us 0.6.
Answer:
ASA
Step-by-step explanation:
in the place that I have put some marks on it, they have the same angle; so then they will also have the same third angle; and for the rest you should use ASA.
