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love history [14]
2 years ago
10

What postulate or theorem can be used to prove that these two triangles are congruent?

Mathematics
1 answer:
Diano4ka-milaya [45]2 years ago
8 0

Answer:

ASA

Step-by-step explanation:

in the place that I have put some marks on it, they have the same angle; so then they will also have the same third angle; and for the rest you should use ASA.

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Find measurement of arc JL.
Tresset [83]
4x-2 + 7x-18 + 6x+6 = 360 degrees

combine like terms

17x-14  = 360

add 14 to both sides

17x =374

 divide both sides by 17
x = 374 / 17 = 22

JL = 7x-18
replace x with 22 and calculate
7(22) - 18 = 154 -18 = 136 degrees

4 0
3 years ago
Whats 70 + 1 =<br><br> help pls
Komok [63]
70 + 1 = 71

Hope I Helped!
5 0
3 years ago
Read 2 more answers
Given f (x ) = x^2 + 3x + 2 and g (x ) = x + 1, perform the indicated operations.
Nana76 [90]

Answer:

(i) (f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2

Step-by-step explanation:

The given functions are;

f(x) = x² + 3·x + 2

g(x) = x + 1

(i) (f - g)(x) = f(x) - g(x)

∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1

(f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = f(x) + g(x)

∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3

(f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = f(x) × g(x)

∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2

(f·g)(x) = x³ + 4·x² + 5·x + 2

7 0
3 years ago
Please solve and please make sure your correct
Mazyrski [523]

Answer:

(a) The ones that are equivalent to the given fraction are: \frac{2}{-9} and -\frac{2}{9}

(b) The one that is equivalent to the given fraction is: \frac{-8}{-5}

3 0
2 years ago
How many times does 6 go into13?
oksano4ka [1.4K]
In order to calculate that, you have to divide 6 from 13
It would be: 13/6 = 2.167

In short, Your Answer would be 2.167

Hope this helps!
7 0
2 years ago
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