All categories

2 years ago

What is the number of sides in a regular polygon when the measure of each interior angle is 162?

Mathematics

1 answer:

Ira Lisetskai [31]2 years ago

8 0

Answer:

Step-by-step explanation:

interior angle + exterior angle = 180°

162° + exterior angle = 180° ( subtract 162° from both sides )

exterior angle = 18°

the sum of the exterior angles of a polygon = 360° , then

number of sides = 360° ÷ 18° = 20

You might be interested in

In the diagram below, which pair of angles is complementary?

Nataly_w [17]

Answer:

/2 and /4 because angle 1 is 90

7 0

3 years ago

A ______ is a rule that pairs each element in one set with exactly one element from a second set.

Cloud [144]

Answer:

function

Step-by-step explanation:

A function is a rule that pairs each element in one set with exactly one element from a second set.

3 0

3 years ago

Kronos Industries bought a desktop for $3,000. It is expected to depreciate at a rate of 10% per year. What will the value of th

kolbaska11 [484]

Answer:

$1968

Step-by-step explanation:

It will depreciate by 10% 4 times, which means that the result in the end will be $3000 * (100% - 10%) * (100% - 10%) * (100% - 10%) * (100% - 10%), or, put simply, x = $3000 * (0.9)⁴.

Power: x = $3000 * 0.6561

Multiply: x = 1968.3 ≈ $1968

4 0

3 years ago

Find the critical points of the function f(x, y) = 8y2x − 8yx2 + 9xy. Determine whether they are local minima, local maxima, or

NARA [144]

Answer:

Saddle point: $(0,0)$

Local minimum: $(\frac{3}{8}, -\frac{3}{8})$

Local maxima: $(0,-\frac{9}{8})$ , $(\frac{9}{8},0)$

Step-by-step explanation:

The function is:

$f(x,y) = 8\cdot y^{2}\cdot x -8\cdot y\cdot x^{2} + 9\cdot x \cdot y$

The partial derivatives of the function are included below:

$\frac{\partial f}{\partial x} = 8\cdot y^{2}-16\cdot y\cdot x+9\cdot y$

$\frac{\partial f}{\partial x} = y \cdot (8\cdot y -16\cdot x + 9)$

$\frac{\partial f}{\partial y} = 16\cdot y \cdot x - 8 \cdot x^{2} + 9\cdot x$

$\frac{\partial f}{\partial y} = x \cdot (16\cdot y - 8\cdot x + 9)$

Local minima, local maxima and saddle points are determined by equalizing both partial derivatives to zero.

$y \cdot (8\cdot y -16\cdot x + 9) = 0$

$x \cdot (16\cdot y - 8\cdot x + 9) = 0$

It is quite evident that one point is (0,0). Another point is found by solving the following system of linear equations:

$\left \{ {{-16\cdot x + 8\cdot y=-9} \atop {-8\cdot x + 16\cdot y=-9}} \right.$

The solution of the system is (3/8, -3/8).

Let assume that y = 0, the nonlinear system is reduced to a sole expression:

$x\cdot (-8\cdot x + 9) = 0$

Another solution is (9/8,0).

Now, let consider that x = 0, the nonlinear system is now reduced to this:

$y\cdot (8\cdot y+9) = 0$

Another solution is (0, -9/8).

The next step is to determine whether point is a local maximum, a local minimum or a saddle point. The second derivative test:

$H = \frac{\partial^{2} f}{\partial x^{2}} \cdot \frac{\partial^{2} f}{\partial y^{2}} - \frac{\partial^{2} f}{\partial x \partial y}$

The second derivatives of the function are:

$\frac{\partial^{2} f}{\partial x^{2}} = 0$

$\frac{\partial^{2} f}{\partial y^{2}} = 0$

$\frac{\partial^{2} f}{\partial x \partial y} = 16\cdot y -16\cdot x + 9$

Then, the expression is simplified to this and each point is tested:

$H = -16\cdot y +16\cdot x -9$

S1: (0,0)

$H = -9$ (Saddle Point)

S2: (3/8,-3/8)

$H = 3$ (Local maximum or minimum)

S3: (9/8, 0)

$H = 9$ (Local maximum or minimum)

S4: (0, - 9/8)

$H = 9$ (Local maximum or minimum)

Unfortunately, the second derivative test associated with the function does offer an effective method to distinguish between local maximum and local minimums. A more direct approach is used to make a fair classification:

S2: (3/8,-3/8)

$f(\frac{3}{8} ,-\frac{3}{8} ) = - \frac{27}{64}$ (Local minimum)