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anzhelika [568]
3 years ago
6

Given the function f(x) = 2(x + 6), find x if f(x) = 22.

Mathematics
1 answer:
Gre4nikov [31]3 years ago
7 0
If f(x)=22 AND f(x)=2(x+6), then 22=2(x+6) and to solve for x it's just:
2x+12=22 -> 2x=10 -> x=5
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A firecracker shoots up from a hill 145 feet high with an initial speed of 80 feet per second. Using the formula H(t) = -16t2 +
kiruha [24]
145 = -16 t² + 80 t +s
s = ?
v = v0 - at
0 = 80 - at
80 = at
s = 80 t - at²/2
s = 80 t - 80t/2
s = 40 t
Finally: 145 = -16 t² + 80 t + 40 t
16 t² - 120 t + 145 = 0
We will solve this quadratic equation:
t = [120 +√ ( (-120)²- 4 · 16 · 145 )] / 32
t = [120 + √ (14400 - 9280) ] / 32 
t = (120 + 71.55) / 32 = 5.98 ≈ 6 s
Answer:D) 6 seconds
3 0
3 years ago
A sodium Isotope has a half life of 15 hours how much sodium is left after 100 hours
JulsSmile [24]
We'll say beginning amount is 100
Ending Amount = Beginning Amount / 2^n  where n is the number of half-lives
100 hours mean six and 2/3 half-lives will elapse
Ending Amount = 100/2^(6.666666)
Ending Amount = 100 / <span> <span> <span> 101.59
</span></span></span>Ending Amount = <span> <span> <span> 0.9843488532 </span> </span> </span>
So if we started with 100 grams after 100 hours (or 6.6666666 half-lives) we would only have <span> <span> 0.9843488532 </span> grams remaining.
http://www.1728.org/halflife.htm

</span>
6 0
3 years ago
A ship is moving at a speed of 30 km/h parallel to a straightshoreline. The ship is 6 km from the shore and it passes alighthous
natita [175]

Answer:

A)  S = f(d) = √(36 + d²)

B)  d = g(t) = 30t

C)  f o g = √(36 + 900t²)

Explanation:  

A) Express the distance s between the lighthouse and the ship as a function of d, the distance the ship has traveled since noon;that is, find f so that s = f(d)

Refer to the attached image and observe that ship starts moving from point I towards point N which represents the position of ship at noon.

From point I to point N ship covers the distance d.

From point I to point L (lighthouse) the distance is S.

A triangle is formed and we want the distance S so we will apply the Pythagorean theorem

IL² = NL² + IN²

S² = 6² + d²

S = √(36 + d²)

Therefore, the function is S = f(d) = √(36 + d²)

B) Express d as a function of t, the time elapsed since noon;that is, find g, so that d = g(t)

Since the ship is moving at a speed of 30 km/h and let t represents the time taken to move from I to N then

d = 30t

or

d = g(t) = 30t

C) Find f o g. What does this function represent?

Since we have already found f(d) and g(t) we can find f o g.

f(d) = √(36 + d²) and d = g(t) = 30t

substitute d = g(t) = 30t into f(d)

f o g = √(36 + (g(t))²)

f o g = √(36 + (30t)²)

f o g = √(36 + 900t²)

This function simply represents the distance from point I to point N to point L which is the longer distance from the initial position of ship to the lighthouse.

7 0
4 years ago
Is 2/3 and 5/6 equivalent
Katyanochek1 [597]
No it is not equivalent




please can i have a brainliest
7 0
4 years ago
Read 2 more answers
Perform the indicated operation. Be sure the answer is reduced.
ANTONII [103]

\frac{m}{n} . \frac{n}{p}  \div  \frac{p}{q}  \\  =  \frac{m}{p}  \div  \frac{p}{q}  \\  =  \frac{m}{p} . \frac{q}{p}  \\  =  \frac{mq}{ {p}^{2} }

Hope it helps...

Regards;

Leukonov/Olegion.

8 0
3 years ago
Read 2 more answers
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