Answer:
Step-by-step explanation:
<u>Given equation</u>:
This is an equation for a horizontal hyperbola.
<u>To complete the square for a hyperbola</u>
Arrange the equation so all the terms with variables are on the left side and the constant is on the right side.
Factor out the coefficient of the x² term and the y² term.
Add the square of half the coefficient of x and y inside the parentheses of the left side, and add the distributed values to the right side:
Factor the two perfect trinomials on the left side:
Divide both sides by the number of the right side so the right side equals 1:
Simplify:
Therefore, this is the standard equation for a horizontal hyperbola with:
3- 3, 6, 9, 12, 15, 18, 21, 24, 27, 30
4- 4, 8, 12, 16, 20, 24, 28, 32, 36, 40
7- 7, 14, 21, 28, 35, 42, 49, 56, 63, 70
HOPE IT HELPED
what prism exactly?
repost the question with the prism
-30
In g(8) the 8 = n. So, substitute 8 in for n in the expression -4n + 2
g(8) = -4(8) + 2 = -32 + 2 = -30
c.
10.98/2=5.49
16.19/3=5.40
21.15/4=5.29
26.85/5=5.37