Answer:
The value of x is ![2\sqrt[3]{2}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B2%7D)
Step-by-step explanation:
We are given 
We need to solve for x
First we subtract 2 both sides

Taking cube roots both sides to isolate x
![x=\sqrt[3]{16}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B16%7D)
Simplify the radical
![x=2\sqrt[3]{2}](https://tex.z-dn.net/?f=x%3D2%5Csqrt%5B3%5D%7B2%7D)
Thus, The value of x is ![2\sqrt[3]{2}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B2%7D)
Answer:
Depending on the equation it will change
n=1 (not in an equation)
Step-by-step explanation:
Pls mark BRAINLIEST
6x10^-4
move 4 places to the left
The answer is 0.0006,
Answer:
Area of the square is 2916
.
Step-by-step explanation:
Let the breadth of the rectangle be represented by w. So that;
length of rectangle = 5w
Area of rectangle = length x breadth
= 5w x w
1620 = 5
divide through by 5 to have,
= 324
w = 
= 18
Thus, the breadth of the rectangle is 18 m.
length = 5 w = 5 x 18
= 90 m
The length of the rectangle is 90 m.
Perimeter of the rectangle = 2(l + w)
= 2( 90 + 18)
= 216 m
Perimeter of a square = 4l
where l is the length of its side.
Given that the perimeters of the rectangle and square are equal, then;
4l = 216
l = 
= 54
length of the side of square is 54 m.
Therefore,
Area of square = 
= 
= 2916
Area of the square whose perimeter is equal to that of the rectangle is 2916
.
Answer: it says $18 plus $3. The equation would be y = 3x + 18 like said. And for the other one it’s y = 5x + 12 following the same logic.
I know I’m not helping much but I’m rushing rn. Hope this helps?