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3 years ago

A printer measuring 25" x

1 answer:

6 0

Let the uniform space wall, surrounding the printer be x", then since the printer is to be centered on a rectangular table, the space at each side of the table is x".

Thus, the dimensions of the table is given by 25" + 2x" by 75 + 2x"

Given that the perimeter of the table is 264, recal that the perimeter of a triangle is 2(length + width), thus
2(25 + 2x + 75 + 2x) = 264
2(100 + 4x) = 264
200 + 8x = 264
8x = 264 - 200 = 64
x = 64/8 = 8

Therefore, the uniform space that will surrond the printer is 8".

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