Let the uniform space wall, surrounding the printer be x", then since the printer is to be centered on a rectangular table, the space at each side of the table is x".
Thus, the dimensions of the table is given by 25" + 2x" by 75 + 2x"
Given that the perimeter of the table is 264, recal that the perimeter of a triangle is 2(length + width), thus 2(25 + 2x + 75 + 2x) = 264 2(100 + 4x) = 264 200 + 8x = 264 8x = 264 - 200 = 64 x = 64/8 = 8
Therefore, the uniform space that will surrond the printer is 8".
