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ElenaW [278]
2 years ago
9

Greg is concerned about the use of ddos attack tools against his organization, so he purchased a mitigation service from his isp

. what portion of the threat model did greg reduce?
Computers and Technology
1 answer:
choli [55]2 years ago
3 0

The threat model implied by Greg to reduce the DDoS attack by buying mitigation service reduces the impact. Thus, option C is correct.

<h3>What is DDoS attack?</h3>

DDoS attack has been an acronym to distributed denial-of-service attack. It is a type of cybercrime that forms the development of the internet traffic over a server, and the overloading forms the user to be enable to access the site operations.

The mitigation service enables the legitimate traffic to reach the server with forming the filter to the server traffic. The buying of service by Greg reduces the impact of the attack. Thus, option C is correct.

Learn more about DDoS attack, here:

brainly.com/question/14052714

#SPJ4

Your question seems to be incomplete, the missing options to the question are:

A. Likelihood

B. Total attack surface

C. Impact

D. Adversary capability

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Answer:

Explanation:

//Include the required header files.

#include<iostream>

using namespace std;

//Define the main function.

int main()

{

//Define the variables.

int i, sum = 0, sqSum = 0, firstNum = 1, secondNum = 0;

char ch;

//Check for valid input.

while (!(firstNum < secondNum))

{

cout << "Enter starting number: ";

cin >> firstNum;

cout<<"Enter ending number(must be > startingNumber): ";

cin >> secondNum;

}

//Store first number in i

i = firstNum;

//Dispaly the number.

cout << "The odd numbers between " << firstNum

<< " and " << secondNum << " are:\n";

//Iterate between first and second number.

while (i <= secondNum)

{

//Check for even numbers.

//Store the sum

if (i % 2 == 0)

sum = sum + i;

//Print the odd numbers

//Evaluate the square of sum of odd number.

else

{

cout << i << " ";

sqSum = sqSum + i * i;

}

//Increase the value of i.

i++;

}

//Dispaly the sum of even numbers.

cout << "\n\nThe sum of the even numbers is:"

<< sum << endl << endl;

//Dispaly the sum of square of odd number.

cout << "The sum of squares the odd numbers is:"

<< sqSum << endl;

//Set i to 1.

i = 1;

//Dispaly the message.

cout << "\nNumber Square\n";

//Iterate and print number between 1 andd 10

//along with the sum.

while (i <= 10)

{

cout << " " << i << "\t " << i * i << endl;

i++;

}

//USe for visual studio.

system("pause");

//Return the value 0.

return 0;

}

Explanation:

The program code will perform the function listed below using loop.

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Hope this helps!

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