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Lapatulllka [165]
1 year ago
7

Find two numbers, both smaller than 150, that have a lowest common multiple of 882 and a highest common factor of 21.

Mathematics
1 answer:
GenaCL600 [577]1 year ago
3 0

Answer:

42 and 21

Step-by-step explanation:

Just divide 882  by  21   to get 42  

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Please help asap!!!!
pentagon [3]

Answer:

A.) 2

B.) 0

C.) 1/3

D.) 1.25

Step-by-step explanation:

A.) 5(2/3)= 2

B.) 5-5= 0

C.) 2(2/3)-1= 1/3

D.) (1/2)+3/4= 1.25

Hope This Helps!  Have A Nice Day!!

3 0
3 years ago
1 - 5p + 6p = 1 + 5p
atroni [7]

Answer:

p=0

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Figure ABCD is rotated by 180 degrees about the origin in the counterclockwise direction to obtain figure A′B′C′D′:
baherus [9]
Hello,
I suppose the picture of A is A', of B is B'.
|AB|=|A'B'|
Rotations keep the distances.

6 0
3 years ago
$i^5+i^{-25}+i^{45}$<img src="https://tex.z-dn.net/?f=%24i%5E5%2Bi%5E%7B-25%7D%2Bi%5E%7B45%7D%24" id="TexFormula1" title="$i^5+i
gregori [183]

i^5+i^{-25}+i^{45}

Rewrite the term i^{-25}

=i^5+\dfrac{1}{i^{25}}+i^{45}

Expand each term so we have

=i(i^2)^2+\dfrac{1}{i(i^2)^{12}}+i(i^2)^{22}

Use the fact that i^2=-1

=i(-1)^2+\dfrac{1}{i(-1)^{12}}+i(-1)^{22}

Use the fact that (-1)^{a}=1 when a is an even number

=i+\dfrac{1}{i}+i

Simplify

=i-i+i

=i

Let me know if you need any clarifications, thanks!

3 0
3 years ago
Read 2 more answers
The general form of an interval estimate of a population mean or population proportion is the _____ plus and minus the _____. le
vodomira [7]

Answer:

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Where :

\hat p represent the point of estimate

And ME = z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} represent the margin of error

For this reason the confidence interval is the point of estimates plus/minus the margin of error

D.) ​point estimate, margin of error

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Where :

\hat p represent the point of estimate

And ME = z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} represent the margin of error

For this reason the confidence interval is the point of estimates plus/minus the margin of error

D.) ​point estimate, margin of error

4 0
3 years ago
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