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Ne4ueva [31]
4 years ago
13

Which ordered pairs are solutions to the inequality y−4x≥−5 ?

Mathematics
1 answer:
zloy xaker [14]4 years ago
5 0
The given inequality is
y - 4x ≥ - 5

To find the correct answer, we should test each answer as shown below.
Test (-2. 1): 
y - 4x = 1 - 4(-2) = 9
It is ≥ -5.
CORRECT

Test (-4, 2)
y - 4x = 2 - 4(-4) = 18
It is ≥ -5
CORRECT

Test (4,0)
y - 4x = 0 - 4(4) = -16
It is < -5
INCORRECT

Test (5,-2)
y - 4x = -2 - 4(5) = -22
It is < -5
INCORRECT

Test (1,-1)
y - 4x = -1 - 4(1) = -5
It is ≥ -5.
CORRECT

Answer: The correct answers are
(-2,1)
(-4,2)
(1,-1)

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3 years ago
Complete each congruence statement by naming the corresponding angle or side (odd questions only)
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Given:

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To find:

The missing values to complete the congruence statements:

1. \overline{IH}\cong \_\_\_\_

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1.

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3.

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\Delta JLK\cong \Delta FGH

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\angle KJL\cong \angle HFG

Therefore, the complete statement is \angle KJL\cong \angle HFG.

4 0
3 years ago
❊ Simplify :
Nataliya [291]
<h3>Need to Do :- </h3>
  • To simplify the given expression .

\red{\frak{Given}}\Bigg\{ \sf \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 }

\rule{200}4

\sf\longrightarrow \small  \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 } \\\\\\\sf\longrightarrow \small  \dfrac{ x-1}{x^2-x -2x +2} +\dfrac{ x-2}{x^2-3x-2x+6} +\dfrac{ x -5}{x^2-5x -3x + 15 } \\\\\\\sf\longrightarrow\small \dfrac{ x -1}{ x ( x - 1) -2(x-1) } +\dfrac{ x-2}{x ( x -3) -2( x -3)} +\dfrac{ x -5}{ x(x-5) -3( x -5) }  \\\\\\\sf\longrightarrow \small \dfrac{ x -1}{ ( x-2) (x-1) } +\dfrac{ x-2}{( x -2)(x-3) } +\dfrac{ x -5}{ (x-3)(x-5)  } \\\\\\\sf\longrightarrow\small \dfrac{ 1}{ x-2} +\dfrac{ 1}{ x -3} +\dfrac{1}{ x -3}   \\\\\\\sf\longrightarrow   \small  \dfrac{1}{x-2} +\dfrac{2}{x-3}  \\\\\\\sf\longrightarrow   \small \dfrac{ x-3 +2(x-2)}{ ( x -3)(x-2) }  \\\\\\\sf\longrightarrow   \small \dfrac{ x - 3 +2x -4 }{ (x-3)(x-2) }     \\\\\\\sf\longrightarrow   \underset{\blue{\sf Required \ Answer  }}{\underbrace{\boxed{\pink{\frak{  \dfrac{ 3x -7}{ ( x -2)(x-3) } }}}}}

\rule{200}4

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