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Ne4ueva [31]
3 years ago
13

Which ordered pairs are solutions to the inequality y−4x≥−5 ?

Mathematics
1 answer:
zloy xaker [14]3 years ago
5 0
The given inequality is
y - 4x ≥ - 5

To find the correct answer, we should test each answer as shown below.
Test (-2. 1): 
y - 4x = 1 - 4(-2) = 9
It is ≥ -5.
CORRECT

Test (-4, 2)
y - 4x = 2 - 4(-4) = 18
It is ≥ -5
CORRECT

Test (4,0)
y - 4x = 0 - 4(4) = -16
It is < -5
INCORRECT

Test (5,-2)
y - 4x = -2 - 4(5) = -22
It is < -5
INCORRECT

Test (1,-1)
y - 4x = -1 - 4(1) = -5
It is ≥ -5.
CORRECT

Answer: The correct answers are
(-2,1)
(-4,2)
(1,-1)

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Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)
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Answer:

(a) The system of the equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. has no solution.

(b) The system of the equations \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. has many solutions y=\frac{2x}{3}-\frac{5}{3}

Step-by-step explanation:

(a) To find the solutions of the following system of equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. you must:

Multiply 2x-3y=3 by 2:

\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}

Subtract the equations

4x-6y=3\\-\\4x-6y=6\\------\\0=-3

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. you must:

Isolate x for 4x-6y=10

x=\frac{5+3y}{2}

Substitute x=\frac{5+3y}{2} into the second equation

16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40

The system has many solutions.

Isolate y for 4x-6y=10

y=\frac{2x}{3}-\frac{5}{3}

3 0
3 years ago
Can anyone help me with 3 and 4
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No as they do not simplify into the same fraction
linear as it the volume is a fraction to the side
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Answer:

here you go

Step-by-step explanation:

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       P = 2  ( 1.6 L  )

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