1 year ago

Helppppp with alll the problems asap!! Show your work

Mathematics

1 answer:

Nikitich [7]1 year ago

6 0

17) $x+2x+1+3x=\boxed{6x+1}$

18) $17-a+5a-1+4ab=\boxed{4ab+4a+16}$

19) $2(3y-5+y+2)=\boxed{8y-6}$

20) $k^2 +k+k^2 -9k+23+k^2 +k+2k^2 -17=\boxed{5k^2 -7k+6}$

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What is the factored form of 6n4 – 24n3 + 18n?

seropon [69]

Answer: Its factored form will be

$6n(n-1)(n^2-3n-3)$

Step-by-step explanation:

Since we have given that

$6n^4-24n^3+18n$

So, we need to factor ,

$6n(n^3-4n^2+3)$

Now,

$\text{Let }p(n)=n^3-4n^2+3$

Now, by hit and trial method, we put n=1,

$p(1)=1^3-4\times1^2+3=1-4+3=1-1=0$

$n=1\\n-1=0$

So, n-1 is also factor of p(n).

Now,

$\frac{n^3-4n^2+3}{n-1}=n^2-3n-3$

So, its factored form will be

$6n(n-1)(n^2-3n-3)$

8 0

3 years ago

Read 2 more answers

How do i calculate this? PV = 100,000(1+0.03)

meriva

Answer:

103,000

Step-by-step explanation:

Use your knowledge of decimal arithmetic. Or, use a calculator.

100,000(1 +.03) = 100,000·1.03 = 1000·103 = 103,000

5 0

2 years ago

Use the Pythagorean Theorem to find the distance to the nearest tenth, between F(9, 5) and G(-2, 2). (Hint: Place F and G on the

artcher [175]

Put a point H on (9, 2). Sketch a triangle out of the three points. Distance between (-2, 2) and (9, 2) is going to be 11. Distance between (9, 2) and (9, 5) is going to be 3. These correspond to the a and b of the Pythagorean Theorem
c^2=a^2+b^2
c=√11^2+3^2=√130
<span>Square root of 130 is 11.4</span>

6 0

3 years ago

Please Help me solve this (Who ever answers correctly will get brainlest)

riadik2000 [5.3K]

Answer: im quite sure it's 4.12

Step-by-step explanation:

im so sure because i got it right <3

5 0

2 years ago

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Can someone please help me with this?

Charra [1.4K]