All categories

3 years ago

What is the slope of a line that is perpendicular to the line represented by the equation y=3/4x-1/2?

1 answer:

5 0

The answer is: " - (4/3) " .
____________________________________
Explanation:
____________________________________
The original equation given has a slope of (3/4).

Note: We know this since the equation for the slope of the line is written in "slope-intercept form" ; also known as: "point-slope form"; that is:

" y = mx + b " ; in which "m" (the coefficient of "x") is the slope.
____________________________________________________
The slope of a line PERPENDICULAR to an equation, when written in "slope-intercept form", is the "negative reciprocal" of the slope of the original line.

Hence, the negative reciprocal of "(3/4)" is: "-(4/3)" .
____________________________________________________

You might be interested in

Rani scores 4 times as many baskets as Layla. Tash scores 8 baskets less than Rani. They score 100 baskets in total. How many ba

Sever21 [200]

Answer:

Tash scores 40 baskets

Step-by-step explanation:

Rani = R

Layla = L

Tash = T

R = 4L

T = 4L-8

As L + R + T = 100

L + 4L + 4L-8 = 100

Collect like terms

9L - 8 = 100

+ 8 both sides

9L = 108

divide by 9 both sides

L = 108 / 9

L = 12

Now..... T = 4L-8 substitute L with 12

T = 48 - 8

T = 40

8 0

3 years ago

How would I put this equation into standard form for a parabola?

Bezzdna [24]

Answer:

fffffffffffffffffffffffffffffff

Step-by-step explanation:

5 0

2 years ago

Please answer this, thanks.

elena55 [62]

First, put it into point-slope form.

Find the slope:

m=(y2-y1)/(x2-x1)
m=(-6-(-2)/(2-1)
m=(-6+2)/1
m=-4/1
m=-4

Now, put it into point-slope:

y-y1=m(x-x1)

y-2=-4(x-(-6)
y-2=-4(x+6)
y-2=-4x-24

Slope intercept form: y= mx+b

Add 2 to the other side.

y=-4x-22 <== the answer

I hope this helps!
~kaikers

4 0

3 years ago

Read 2 more answers

How do I simplify the fraction 125/186

pogonyaev

125/186 cannot be simplified. It is already in simplest form.

6 0

3 years ago

Find m∠A given ΔABC where a=4, b=6, c=3.

igomit [66]

For this question, we're going to use the law of cosines.
The law of cosines is the following equation:

$a^2=b^2+c^2-2(b)(c) \cos(A)$

We know the values of a, b, and c. We want to find the measure of angle A.
$a=4$
$b=6$
$c=3$

Now, plug in these values into the equation.

$4^2=6^2+3^2-2(3)(6) \cos(A)$
$16=45-36 \cos(A)$

Add both sides by $36 \cos(A)$ and subtract both sides by 16

$36 \cos(A)=29$

Divide both sides by 36

$\cos(A)= \dfrac{29}{36}$

Take the inverse cosine, or arc cosine, of both sides.
Using a calculator, you'll get the following result.

$A \approx 36.3^O$

The measure of angle A should be 36.3 degrees. Hope this helps! :)

4 0

3 years ago