Si en un grupo 20 niños representan el 80% Cuántos son el 20% restante

An object moving north with an initial velocity of 14m/s accelerates 5m/s squared. What is the final velocity of the object?

OLEGan [10]

The final velocity of the object is 16m\s.
Hope this helps! :)

6 0

3 years ago

You stand new the earth's equator. A positively charged particle that starts moving parallel to the surface of the earth in a st

Talja [164]

Answer:

c. from south to north

Explanation:

since we know that:

F = qv×B

where F is the force and in this case is pointed upward

where v is the velocity due east

the field must be due north by the right hand rule

Therefore, near the equator the magnetic field lines of the earth are directed north from south

3 0

3 years ago

2000, the Millennium Bridge, a new footbridge over the River Thames in London, England, was opened to the public. However, after

sweet [91]

Answer:

n = 1810

A = 25 mm

Explanation:

Given:

Lateral force amplitude, F = 25 N

Frequency, f = 1 Hz

mass of the bridge, m = 2000 kg/m

Span, L = 144 m

Amplitude of the oscillation, A = 75 mm = 0.075 m

time, t = 6T

now,

Amplitude as a function of time is given as:

$A(t)=A_oe^{\frac{-bt}{2m}}$

or amplitude for unforce oscillation

$\frac{A_o}{e}=A_oe^{\frac{-b(6T)}{2m}}$

or

$\frac{6bt}{2m}=1$

or

$b=\frac{m}{3T}$

Now, provided in the question Amplitude of the driven oscillation

$A=\frac{F_{max}}{\sqrt{(k-m\omega_d^2)+(b\omega_d^2)}}$

the value of the maximum amplitude is obtained $(k=m\omega_d^2)$

thus,

$A=\frac{F_{max}}{(b\omega_d}$

Now, for n people on the bridge

Fmax = nF

thus,

max amplitude

$0.075=\frac{nF}{((\frac{m}{3T})2\pi}$

or

n = 1810

hence, there were 1810 people on the bridge

b) $A=\frac{F_{max}}{(b\omega_d}$

since the effect of damping in the millenium bridge is 3 times

thus,

b=3b

therefore,

$A=\frac{F_{max}}{(3b\omega_d}$

or

$A=\frac{1}{(3}A_o$

or

$A=\frac{1}{(3}0.075$

or

A = 0.025 m = 25 mm

6 0

3 years ago

Increasing the temperature of object by 20K = C *

Whitepunk [10]

Answer:

B

Explanation:

6 0

3 years ago

1 point

Darya [45]

Given that,

Mass of object, m = 55 kg

Mechanical energy of the object, M = 4306 J

Potential energy, P = 2940 J

We know that the mechanical energy is the sum of kinetic and potential energy such that,

Mechanical energy = kinetic energy + potential energy

$K=M-P\\\\K=4306-2940\\\\K=1366\ J$

Kinetic energy is given by :

$K=\dfrac{1}{2}mv^2$ v is velocity of object

$v=\sqrt{\dfrac{2K}{m}} \\\\v=\sqrt{\dfrac{2\times 1366}{55}} \\\\v=7.04\ m/s$

So, the velocity of object is 7.04 m/s.

7 0

3 years ago