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faust18 [17]
3 years ago
13

How much work will a machine with a power rating of 1.1 × 103 watts do in 2.0 hours?

Physics
2 answers:
lyudmila [28]3 years ago
7 0

Answer:

D.

Explanation:

8.1X10 to the power of 6 Joules.

Pie3 years ago
4 0

Answer:

7.92×10^6Joules

Explanation:

Power is defined as the rate of change in work done. Mathematically, Power = Workdone/Time

Given power = 1.1×10³watts

Time = 2.0hours = 2×60×60

= 7,200seconds

Workdone = power × time

Work done = 1.1×10³×7200

Workdone = 7,920,000Joules

= 7.92×10^6Joules

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A book is on the table. If the weight of the book is 25 newtons, what is the magnitude and direction of the normal force?
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I'm not sure about the magnitude, but the direction of the normal force is upward. 
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What is the unit of the quotient of inductance and resistance?
Scorpion4ik [409]

The unit of the quotient of inductance and resistance will be Henry and ohm

Inductance is the tendency of an electrical conductor to oppose a change in the electric current flowing through it. The flow of electric current creates a magnetic field around the conductor. The field strength depends on the magnitude of the current, and follows any changes in current.

Resistance is a measure of the opposition to current flow in an electrical circuit. Resistance is measured in ohms, symbolized by the Greek letter omega (Ω). Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who studied the relationship between voltage, current and resistance.

unit of quotient of inductance = henry (H)

unit of resistance = ohm

To learn more about resistance here

brainly.com/question/14547003

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3 0
2 years ago
Explain how the sun's position in the sky affects the length of shadows
Serggg [28]

A shadow forms on the side of an object that faces away from the sun. The length of shadows changes as Earth rotates. In the morning, the sun is low in the eastern sky and shadows are long. As time passes in the morning, the sun seems to move higher in the sky.

8 0
3 years ago
Mester Exam 1 11 of 35
frez [133]
Please show picture of diagrams
8 0
3 years ago
As a way of determining the inductance of a coil used in a research project, a student first connects the coil to a 5.62 V batte
Reptile [31]

Answer:

Its inductance L = 166 mH

Explanation:

Since a current, I = 0.698 A is obtained when a voltage , V = 5.62 V is applied, the resistance of the coil is gotten from V = IR

R = V/I = 5.62/0.698 = 8.052 Ω

Since we have a current of I' = 0.36 A (rms) when a voltage of V' = 35.1 V (rms) is applied, the impedance Z of the coil is gotten from

V₀' = I₀'Z where V₀ = maximum voltage = √2V' and I₀ = maximum current = √2I'

Z = V'/I' = √2 × 35.1 V/√2 × 0.36 V = 97.5 Ω

WE now find the reactance X of the coil from

Z² = X² + R²

X = √(Z² - R²)

= √(97.5² - 8.05²)

= √(9506.25 - 64.8025)

= √9441.4475

= 97.17 Ω

Now, the reactance X = 2πfL where f = frequency of generator = 93.1 Hz and L = inductance of coil.

L = X/2πf

= 97.17/2π(93.1 Hz)

= 97.17 Ω/584.965 rad/s

= 0.166 H

= 166 mH

Its inductance L = 166 mH

5 0
3 years ago
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