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Nina [5.8K]
1 year ago
12

How does extracellular glucose inhibit transcription of the lac operon?

Biology
1 answer:
Genrish500 [490]1 year ago
3 0

The extracellular glucose inhibit transcription of the lac operon (D) by reducing the levels of intracellular cAMP.

Lac operon is the assembly of various genes that are involved in the uptake and metabolism of lactose of E. coli or any other bacteria. It consists of a regulator gene, promoter gene, operator and structural gene. Structural genes are three: z, y and a. Each codes for a different enzyme.

cAMP is the cyclic Adenosine Monophosphate. It is produced by the bacteria when there are low levels of glucose in it. Hence it is also named as hunger signals. Therefore, cAMP is responsible for activating the operon to produce lactose.

To know more about cAMP, here

brainly.com/question/13794408

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<span>Answer: Blood leaves the left ventricle through the aorta.

The blood that is pumped from the heart and goes through all of the body structures, that need to be irrigated, leaves from the left ventricle. This ventricle will contract and push the blood to go to the aorta. From there, goes to the rest of the body.
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The results of genetic crosses derived from Punnet squares assume that each gamete contains one allele for each trait, which com
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Independent assortment

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What is not part of the endomembrane system?
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