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1 year ago

4a²-ab-3b²solve this

Mathematics

1 answer:

Ainat [17]1 year ago

7 0

Answer: (4a+3b)(a−b)

Step-by-step explanation:

Factor by grouping

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A) 79.2 C) 11.9 B) 8.9 D) 11.6

vova2212 [387]

Answer:

789

Step-by-step explanation:

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2 years ago

Please help answer number 4!

solong [7]

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3 years ago

Pre cal help??????????

klasskru [66]

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3 years ago

the price of jet fuel in north america during the last week of 2012 was recorded as $3,062 for 1,000 gallons. What was the unit

Andrews [41]

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3 years ago

I need help with this question

Murrr4er [49]

The number of cows is given by

$14\cdot 2^{\frac{y}{5}}$

So, after $k$ years, the number of cows will be

$14\cdot 2^{\frac{y+k}{5}}$

We want this number to be twice as much as the original:

$14\cdot 2^{\frac{y+k}{5}} = 2(14\cdot 2^{\frac{y}{5}})$

First of all, we can cancel 14 from both sides:

$2^{\frac{y+k}{5}} = 2\cdot 2^{\frac{y}{5}}$

Finally, on the right hand side, we can use the exponent rule

$a^b\cdot a^c=a^{b+c}$

to get

$2^{\frac{y+k}{5}} = 2^{\frac{y}{5}+1}$

To solve this equation, we must impose that the two exponents are the same:

$\dfrac{y+k}{5} = \dfrac{y}{5}+1 \iff \dfrac{y+k}{5} = \dfrac{y+5}{5}$

And clearly this is true if and only if $k=5$ . So, it will take 5 years for the cow heard to double in number.

You can do the exact same steps to find the doubling time for the sheeps.

8 0

3 years ago

4a²-ab-3b²solve this ​

4a²-ab-3b²solve this