I want to say either rectangular prisim or triangle pyrimad
Answer:
Do you want to be extremely boring?
Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?
is a valid solution.
Want something more fun? Why not a parabola? 
.
At this point you have three parameters to play with, and from the fact that 
we can already fix one of them, in particular 
. At this point I would recommend picking an easy value for one of the two, let's say 
(or even 
, it will just flip everything upside down) and find out b accordingly:
Our function becomes
Notice that it works even by switching sign in the first two terms: 
Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: 
Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need 
, and at that point the first condition is guaranteed; using the second to find k we get 
Or how about a sine wave that oscillates around 2? with a similar reasoning you get
Sky is the limit.
Answer:
(1,2)
Step-by-step explanation:
The solution to the system is where the two lines cross.
They cross at x=1 and y=2
(1,2)
Answer:
8587 should be in the box
Step-by-step explanation:
we would see it question as: 12/- 8587
12 goes into 85 7 times, so 7
12 goes into 18 1 time, so 1
12 goes into 67 5 times, so 5
then the remainder is 7
or you further divide to get . 5 8 3333333...
so your answer should be 715r7 or 715.58333
I believe the answer is 5. I multiplied 5 to -4 and that’s -20 and I’m guessing since slope-intercept form is y=Mx+b I’m thinking b=4 and the slope being 5 matches the output. -16=5(-4)+4
