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zysi [14]
3 years ago
8

Does anyone know whoever answers i’ll mark brainlist

Mathematics
1 answer:
-Dominant- [34]3 years ago
8 0

Answer:

(1,2)

Step-by-step explanation:

The solution to the system is where the two lines cross.

They cross at x=1 and y=2

(1,2)

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aron lei is making identical balloon arrangements for a party. He has 32 maroon balloons and 24 white balloons, he wants each ar
alexandr402 [8]

Answer:

The greatest number of arrangements that he can make if every balloon is used is 8.

Step-by-step explanation:

The greatest number of arrangements will be the greatest common factor between 24 and 32.

GCF of 24 and 32:

We keep factoring both numbers by prime factors, while they can both be divided by the same number. So

24 - 32|2

12 - 16|2

6 - 8|2

3 - 4

There is no factor for which we can divide both 3 and 4. So the GCF is 2*2*2 = 8.

This means that the greatest number of arrangements that he can make if every balloon is used is 8.

5 0
3 years ago
Click on the words to go to the picture
Sati [7]
The answer is 2,187 you keep multiplying the exponets
8 0
3 years ago
Quick algebra 1 question for 10 points!
Anna35 [415]

<u>Answer:</u>

h(-2) =\boxed{ \bf -111}

<u>Step-by-step explanation:</u>

The function h(x) is defined as:

h(x) = 12x^3 - 15

To calculate the value of h(-2), we have to replace the x in the definition of h(x) with -2:

h(-2) = 12(-2)^3 - 15

       ⇒ 12(-8) -15

       ⇒ -96 - 15

       ⇒ -111

       

3 0
2 years ago
Read 2 more answers
If f(x)=2/(x-3) and g(x)=6/x, find (g·f)(x)
pishuonlain [190]

(g\circ f)(x)=\dfrac{6}{\dfrac{2}{x-3}}=6\cdot\dfrac{x-3}{2}=3x-9\\\\\\ (g\cdot f)(x)=\dfrac{6}{x}\cdot \dfrac{2}{x-3}=\dfrac{12}{x^2-3x}

3 0
3 years ago
How do I solve this?
Kryger [21]
     y = abˣ
   20 = ab¹
   20 = ab
    b      b
20/b = a

 y = abˣ
 4 = (20/b)b²
 4 = 20b
20    20
¹/₅ = b

   y = abˣ
 20 = ¹/₅b¹
 20 = ¹/₅b
  ¹/₅     ¹/₅
100 = b

y = abˣ
y = 100(0.2)ˣ
4 0
3 years ago
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