when using coordinates in your drawings you may need to get an exact coordinate value of a point. What command do you use

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When using coordinates in your drawings, you may need to get an exact coordinate value of a point.

For example, it might be the corner of an object for setting out the purpose or the center of a circle for modifying the circle position.

What do we mean by coordinates?

Coordinates are distances or angles, represented by numbers, that uniquely identify points on surfaces of two dimensions (2D) or in space of three dimensions ( 3D ).
There are several coordinate schemes commonly used by mathematicians, scientists, and engineers.

To Display the Coordinates of a Point-

Click Home tab - > Utilities board - > ID Point.

Click the area that you need to distinguish.

The X, Y, Z coordinate qualities are shown in the Command brief.

With object snaps turned on, you can choose an item and see the directions for a component like an endpoint, midpoint, or focus.
At the point when an order prompts you for a point, you can utilize the guiding gadget to determine the point, or you can enter its directions.
At the point when dynamic information is turned on, you can enter the direction esteems in a tooltip close to the cursor.

Learn more about coordinates

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The complete question is -

When using coordinates in your drawings, you may need to get an exact coordinate value of a point. For example, it might be the corner of an object for setting out purpose, or the center of a circle for modifying the circle the circle position. what command do you use to obtain a point's exact coordinate value?

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write an equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

dimaraw [331]

The equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4) is $y - 3 = \frac{-7x}{2}+ \frac{21}{4}$

<h3>Solution:</h3>

Given that we have to write equation in point-slope form for the perpendicular bisector of the segment with endpoints at A(-2,2) and B(5,4)

Let us first find the slope of given line AB

The slope "m" of the line is given as:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Here the given points are A(-2,2) and B(5,4)

$\text {Here } x_{1}=-2 ; y_{1}=2 ; x_{2}=5 ; y_{2}=4$

$m=\frac{4-2}{5-(-2)}=\frac{2}{7}$

Thus the slope of line with given points is $\frac{2}{7}$

We know that product of slopes of given line and slope of line perpendicular to given line is always -1

$\begin{array}{l}{\text {slope of given line } \times \text { slope of perpendicular bisector }=-1} \\\\ {\frac{2}{7} \times \text { slope of perpendicular bisector }=-1} \\ \\{\text {slope of perpendicular bisector }=\frac{-7}{2}}\end{array}$